500 is the answer because 500 is much closer
Answer:
C) 0 ≤ x ≤ 25
Step-by-step explanation:
We are supposed to find a reasonable constraint so that the function is at least 300 i.e. the value of x at which f(x) is greater or equal to 300
A)x ≥ 0
Refer the graph
At x = 0
f(x)=300
On increasing the value of x , f(x) increases but at x = 12 it starts decreasing
So, x ≥ 0 can also have f(x)<300
So, Option A is wrong
B)−5 ≤ x ≤ 30
At x = -5
f(x) = 100
So, Option B is wrong since we require f(x) is greater or equal to 300
c)0 ≤ x ≤ 25
At x = 0
f(x)=300
At x = 12 , it starts decreasing
At x = 25
f(x)=300
So, The value of f(x) is at least 300 when 0 ≤ x ≤ 25
D)All real numbers
At x = 30
f(x)=0
But we require f(x) greater or equal to 300
Hence Option C is true
We'll use the slope-intercept form y = mx + b. Where m is the slope and b is the y-intercept.
We know the slope, -1/5. Now the equation looks like y = (-1/5)m + b
To find the y-intercept, plug in the ordered pair that the question gave us into our equation and solve for b.
7 = (-1/5)(-3) + b
7 = 0.6 + b
6.4 = b
b = 6 2/5
So, the y-intercept will be at 6 2/5.
Answer:
1.5 because it is the average of the two middle numbers in this scenario.
Answer:
Step-by-step explanation:
1) elimination
2) elimination
3)add
4)subtract
5) Variable
6) add
7) eliminate
8) subtract
9) eliminate
10) adding
11) adding
12) 2
13)2
14) 0
15) (2 , 0)
16) (2 , 0)
17) solution
