Answer:
404.990 in^2
Step-by-step explanation:
I think, I cant be 100% sure but I'm pretty sure that's the answer, sorry if I'm wrong
Answer:
14
Step-by-step explanation:
When there are 2 -, they both create a +. the brackets are removed and you get 4--10, which is equal to 4+10 which = 14
Answer:
Step-by-step explanation:
Answer:
20°
Step-by-step explanation:
40°, 70° and 90° are the measures of the three angles of the quadrilateral.
Measure of fourth angle of the Quadrilateral
= 360° - (40° + 70° + 90°)
= 360° - 200°
= 160°
Measure of angle 1 will be equal to the measure of the linear pair angle of 160° as they are corresponding angles.
Thus,


Alternate method:
![m\angle 1 = 180\degree- [360\degree-(40\degree+70\degree+90\degree)]](https://tex.z-dn.net/?f=m%5Cangle%201%20%3D%20180%5Cdegree-%20%5B360%5Cdegree-%2840%5Cdegree%2B70%5Cdegree%2B90%5Cdegree%29%5D)
![\implies m\angle 1 = 180\degree- [360\degree-200\degree]](https://tex.z-dn.net/?f=%5Cimplies%20m%5Cangle%201%20%3D%20180%5Cdegree-%20%5B360%5Cdegree-200%5Cdegree%5D)


Answer:
$712.
Step-by-step explanation:
We have been given that a fund earns a nominal rate of interest of 6% compounded every two years. We are asked to find the amount that must be contributed now to have 1000 at the end of six years.
We will use compound interest formula to solve our given problem.
, where,
A = Final amount,
P = Principal amount,
r = Annual interest rate in decimal form,
n = Number of times interest is compounded per year,
t = Time in years.

Since interest is compounded each two years, so number of compounding per year would be 1/2 or 0.5.







Therefore, an amount of $712 must be contributed now to have 1000 at the end of six years.