3 years ago

If c(x)=5/x-2 and d(x)=x+3, what is the domain of (cd)(x)?

Mathematics

1 answer:

pickupchik [31]3 years ago

3 0

Answer:

The domain is all Real x except x = 2 .

Step-by-step explanation:

(cd)(x) = ( 5 / x-2) * x+3

= 5(x+3)/(x-2)

The domain is all Real x except x = 2 .

(because when x = 2 (cd)(x) is undefined).

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5.<br> {wawawawawawawawawawawa}

Harrizon [31]

Answer:

35mc

Step-by-step explanation:

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2 years ago

A grocer has two kinds of tea, one selling for 80 cents per pound and the other selling for 60 cents per pound. How many pounds

ruslelena [56]

X*80+y*60= 50*74
x +y =50 | * ( -60)

80x + 60y= 50*74
-60x - 60y=-50*60
---------------------------
20x= 50*(74-60)=50*14
x=50*14/20=35 pounds of 80 cents tea
y=50-35=15 pounds of 60 cents tea

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2 years ago

F(x) = -4x - 3<br> Evaluate f(9) + f(5)=

RSB [31]

Evaluate f(9) + f(5)= 14f If I didn't answer Your Question fully than tell me please!

7 0

3 years ago

One-third cup of black beans provides 20% of the potassium you need daily. You must get the remaining 1,360 milligrams from othe

Elis [28]

80 percent of needed milligrams is 1360
so

1360/.80 = x/1

Answer: 1700 milligrams

3 0

3 years ago

What is f–1(8)??<br><br> Please select the best answer

notka56 [123]

Answer:

$f^{-1}(8)=\frac{3}{2}$

Step-by-step explanation:

Given f(x)= $2x+5$

We have to find $f^{-1}(8)$

In order to find $f^{-1}(x)$ we have to make x as the subject of the formula

Let us assume f(x)=y

⇒ $2x+5=y$

Subtracting both sides by 5

$2x+5-5=y-5$

$2x=y-5$

Dividing both sides by 2

$\frac{2x}{2}=\frac{y-5}{2}$

⇒ $x=\frac{y-5}{2}$

Now substituting y with x

we have $f^{-1}(x)=\frac{x-5}{2}$

Now $f^{-1}(8)=\frac{8-5}{2}$

= $\frac{3}{2}$

So option (ii) is correct

5 0

2 years ago

Read 2 more answers