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2 years ago

Find the probability of having 2, 3, or 4

Mathematics

1 answer:

denis-greek [22]2 years ago

3 0

Answer:

16% for 2 successes, 6.4% for 3 successes, 2.6% for 4 successes, and 1% for 5 successes

Step-by-step explanation:

Since the success rate of a binomial experiment is 40%, converted to 0.4, you get the equation of f(x) = (0.4)^x, for where x is the amount of successful experiments

For the success of 2 experiments:

f(2) = (0.4)^2

=0.16 => 16%

For the success of 3 experiments:

f(3) = (0.4)^3

= 0.064 => 6.4%

For the success of 4 experiments:

f(4) = (0.4)^4

= 0.0256 => 2.56% => ~2.6

For the success of 5 experiments:

f(5) = (0.4)^5

= 0.01024 => 1.024% => ~1%

Your welcome and comment if you have any questions :)

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Jake tossed a paper cup 50 times and recorded how it landed. The table shows the results:

Dmitry [639]

Hello!

Here are 6 steps to Help You Out!

1. 3 divided by 50 = .06

2. Then if you like you can turn it in to a percent not sure how the answer is supposed to look for example:

3. 3/50=6/100=6%

4. 7 divided by 50 - .14

5. so 0.06 for the first one

6. And 40 divided by 50 = .8

====>So as we can see, open side up .06 closed side up .14 and on its side .8 or open 6% closed 14% and side 80% chance.<====

Hope this Helps! Have A WONDERFUL Day! :)

8 0

3 years ago

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

3 years ago

Evaluate f(x) = sqrt(5x + 4) for x = 12

Nezavi [6.7K]

Answer is 8

Work Shown:

f(x) = sqrt(5*x + 4)

f(12) = sqrt(5*12 + 4) ... replace every x with 12

f(12) = sqrt(60 + 4)

f(12) = sqrt( 64 )

f(12) = 8

8 0

3 years ago

Is 7/8 or 11/10 closer to 1? How did you decide anybody help please?

erik [133]

Let

A-----> $\frac{7}{8}$

B-----> $\frac{11}{10}$

C-----> $1$

we know that

Point A-------> Multiply numerator and denominator by $10$

$\frac{7*10}{8*10} =\frac{70}{80}$

Point B-------> Multiply numerator and denominator by $8$

$\frac{11*8}{10*8} =\frac{88}{80}$

Point C-------> Multiply numerator and denominator by $80$

$\frac{1*80}{1*80} =\frac{80}{80}$

Find the distance Point A to Point C

$\frac{80}{80} -\frac{70}{80} =\frac{10}{80}$

Find the distance Point B to Point C

$\frac{88}{80} -\frac{80}{80} =\frac{8}{80}$

therefore

$\frac{8}{80} < \frac{10}{80}$

Point B is closer to Point C

$\frac{11}{10}$ is closer to $1$

the answer is

$\frac{11}{10}$ is closer to $1$

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3 years ago

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a washer and dryer cost $751 combined the washer cost $51 more than the dryer what is the cost of the dryer

marysya [2.9K]

Answer:350

Step-by-step explanation:700 divided by 2

5 0

3 years ago

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