The distance the spring will be stretched with an object weighing 29 kilograms is 47 centimeters
<h3>Variation</h3>
From the question, we are to determine the distance the spring will be stretched with an object weighing 29 kg
From the given information,
The distance, D, that a spring is stretched by a hanging object varies directly as the weight, W, if the object
That is,
D ∝ W
Then, we can write that
D = kW
NOTE: k is the constant of proportionality
Also, from the given information,
An object weighing 30 kilograms stretched the spring 49 centimeters
That is,
D = 49 cm
W = 30 kg
Putting the parameters into the equation to solve for k, we get
49 = k × 30
∴ k = 49/30
Now, for the distance stretched when weight is 29 kg
Using D = kW, we get
D = (49/30) × 29
D = 1421/30
D = 47.367
D ≅ 47 cm
Hence, the distance the spring will be stretched with an object weighing 29 kilograms is 47 centimeters
Learn more on Variation here: brainly.com/question/1523102
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