Question

The distance, D, that a spring is stretched by a hanging object varies directly as the weight, W, if the object. An object weighing 30 kilograms stretched the spring 49 centimeters. Determine the distance the spring will be stretched with an object weighing 29 kilograms. Round your answer to the nearest centimeter.

Answer 1

The distance the spring will be stretched with an object weighing 29 kilograms is 47 centimeters

Variation

From the question, we are to determine the distance the spring will be stretched with an object weighing 29 kg

From the given information,

The distance, D, that a spring is stretched by a hanging object varies directly as the weight, W, if the object

That is,

D ∝ W

Then, we can write that

D = kW

NOTE: k is the constant of proportionality

Also, from the given information,

An object weighing 30 kilograms stretched the spring 49 centimeters

That is,

D = 49 cm

W = 30 kg

Putting the parameters into the equation to solve for k, we get

49 = k × 30

∴ k = 49/30

Now, for the distance stretched when weight is 29 kg

Using D = kW, we get

D = (49/30) × 29

D = 1421/30

D = 47.367

D ≅ 47 cm

Hence, the distance the spring will be stretched with an object weighing 29 kilograms is 47 centimeters

Learn more on Variation here: brainly.com/question/1523102

#SPJ1