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irga5000 [103]
2 years ago
6

Naysha listens to the radio for five-sixths of an hour each day. which expressions represent the time naysha spends listening to

the radio in a 7-day period? check all that apply.
twelve-sixths
five-sixths plus five-sixths plus five-sixths plus five-sixths plus five-sixths plus five-sixths plus five-sixths
startfraction 35 over 6 endfraction
7 times five-sixths
7 plus five-sixths
Mathematics
1 answer:
Yakvenalex [24]2 years ago
5 0

The time Natasha listens to the radio can be represented as 7 times five sixths, 35/6 or 5/6 + 5/6 + 5/6 + 5/6 + 5/6.

<h3>How to find out the time Natasha listens to the radio in one week?</h3>
  • Time per day: 5/6 of an hour
  • Time per week: 5/6 + 5/6 + 5/6 + 5/6 + 5/6 = 35/6

or 5/6 x 7 = 35/6

<h3>How to represent this?</h3>

There are three options:

  • 5/6 + 5/6 + 5/6 + 5/6 + 5/6
  • 35/6
  • 5/6 x 7

Learn more about fractions in: brainly.com/question/10354322

#SPJ1

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What is the answer to 1/9 + 3/5
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3(4*5)=(3*4)5 what is thsi
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This is the associative property. Basically if you move the parenthesis either to left or right you’ll still get the right answer. So 4 times 5 equals 20 and 20 times 3 equals 60. 3 x 4 equals 12 and 12 x 5 equals 60
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A water storage tank has the shape of a cylinder with diameter 14 ft. It is mounted so that the circular cross-sections are vert
andrezito [222]

Answer:

percentage of the total capacity is 75.6%

Step-by-step explanation:

Hello! To solve this problem we follow the following steps

1. draw the complete scheme of the problem (see attached image)

2. To solve this problem we must find the area of ​​the circular sector using the following equation.(c in the second attached image)

A=\frac{R^2}{2} (\alpha -sin\alpha )

\alpha =2arccos(\frac{d}{R})

3. observing the attached images we replace the values ​​in the equations and find the area of ​​the circular sector, remember that you must transform the angle to radians

\alpha =2arccos(\frac{5}{7})=88.83

A=\frac{R^2}{2} (\alpha -sin\alpha )\\A=\frac{7^2}{2} (88.83-sen88.83)*\frac{\pi rad}{180} =37.57ft^2

4.we calculate the area of ​​the total circle (At), then subtract the area of ​​the circular sector (Ac) to find the area occupied by water (Aw)

At=\frac{\pi }{4} (14ft)^2=153.93ft^2

Aw=At-Ac=153.93-37.57=116.36ft^2

5.Finally, we calculate the percentage that represents the water in the tank by dividing the area of ​​the water over the total area of ​​the tank

\frac{116.36}{153.93} *100=75.6

percentage of the total capacity is 75.6%

3 0
3 years ago
Suppose that administrators at a large urban high school want to gain a better understanding of the prevalence of bullying withi
boyakko [2]

Answer:

lower limit =0.261

upper limit =0.369

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Description in words of the parameter p

p represent the real population proportion of people that have experienced bullying

X= 63 people in the random sample that have experienced bullying

n=200 is the sample size required  

\hat p=\frac{63}{200}=0.315 represent the estimated proportion of people that have experienced bullying

z_{\alpha/2} represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

\hat p=\frac{63}{200}=0.315 represent the estimated proportion of people that they were planning to pursue a graduate degree

Confidence interval

The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 90% confidence interval the value of \alpha=1-0.90=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.64  

And replacing into the confidence interval formula we got:  

0.315 - 1.64 \sqrt{\frac{0.315(1-0.315)}{200}}=0.261  

0.315 - 1.64 \sqrt{\frac{0.315(1-0.315)}{200}}=0.369  

And the 90% confidence interval would be given (0.261;0.369).  

We are confident at 90% that the true proportion of people that they were planning to pursue a graduate degree is between (0.261;0.369).  

lower limit =0.261

upper limit =0.369

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