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irga5000 [103]
2 years ago
6

Naysha listens to the radio for five-sixths of an hour each day. which expressions represent the time naysha spends listening to

the radio in a 7-day period? check all that apply.
twelve-sixths
five-sixths plus five-sixths plus five-sixths plus five-sixths plus five-sixths plus five-sixths plus five-sixths
startfraction 35 over 6 endfraction
7 times five-sixths
7 plus five-sixths
Mathematics
1 answer:
Yakvenalex [24]2 years ago
5 0

The time Natasha listens to the radio can be represented as 7 times five sixths, 35/6 or 5/6 + 5/6 + 5/6 + 5/6 + 5/6.

<h3>How to find out the time Natasha listens to the radio in one week?</h3>
  • Time per day: 5/6 of an hour
  • Time per week: 5/6 + 5/6 + 5/6 + 5/6 + 5/6 = 35/6

or 5/6 x 7 = 35/6

<h3>How to represent this?</h3>

There are three options:

  • 5/6 + 5/6 + 5/6 + 5/6 + 5/6
  • 35/6
  • 5/6 x 7

Learn more about fractions in: brainly.com/question/10354322

#SPJ1

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Prove that a triangle with the sides a - 1 cm to root under a ​
vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.  

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm  

Hence,

{AB}^2 = (a -1)^2 

Now We know that

(a- b)^2 = a^2+b^2 - 2ab

So;

{AB}^2= a^2 + 1^2 -2\times a \times1

{AB}^2 = a^2 + 1 -2a

Now;

{BC}^2 = (2\sqrt{a})^2= 4a

Also;

{CA}^2 = (a + 1)^2

Now We know that

(a+ b)^2 = a^2+b^2 + 2ab

{CA}^2= a^2 + 1^2 +2\times a \times1

{CA}^2 = a^2 + 1 +2a

{CA}^2 = AB^2 + BC^2

[By Pythagoras theorem]

a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a

Hence, {CA}^2 = AB^2 + BC^2

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0
3 years ago
The graph below shows the solution to a system of inequalities: Solid line joining ordered pairs 0, 3.75 and 15, 0. Shade the po
algol [13]
(0,3.75)(15,0)
slope(m) = (0 - 3.75) / (15 - 0) = -3.75/15 = - 0.25 or -1/4

y = mx + b
slope(m) = -1/4
(15,0)...x = 15 and y = 0
now we sub
0 = -1/4(15) + b
0 = -15/4 + b
15/4 = b

y = -1/4x + 15/4
1/4x + y = 15/4....multiply by 4
x + 4y = 15.....and since it is a solid line, it contains an equal sign...and since it is shaded above the line, it is greater.
so ur inequality is : x + 4y > = 15 (thats greater then or equal)
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