Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that

So;


Now;

Also;

Now We know that




[By Pythagoras theorem]

Hence, 
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
(0,3.75)(15,0)
slope(m) = (0 - 3.75) / (15 - 0) = -3.75/15 = - 0.25 or -1/4
y = mx + b
slope(m) = -1/4
(15,0)...x = 15 and y = 0
now we sub
0 = -1/4(15) + b
0 = -15/4 + b
15/4 = b
y = -1/4x + 15/4
1/4x + y = 15/4....multiply by 4
x + 4y = 15.....and since it is a solid line, it contains an equal sign...and since it is shaded above the line, it is greater.
so ur inequality is : x + 4y > = 15 (thats greater then or equal)
Answer:
D
Step-by-step explanation:
1. calculate the expression
2.multiple reorder
3.remove parenthesis
Answer:
idk
Step-by-step explanation:
Answer:
Answer is 1.5g/m^3 Hope it will help you.