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marysya [2.9K]
3 years ago
5

An adolescent has a weight of 127 pounds. The doctor requires you to record the patient’s weight in kilograms. Convert 127 pound

s to kilograms.
Mathematics
2 answers:
olasank [31]3 years ago
6 0

The amount of kilograms he weighs I think is 57.6062994983

Soloha48 [4]3 years ago
3 0

Answer:

57.606184 kilograms

Step-by-step explanation:

Given :An adolescent has a weight of 127 pounds.

To Find : Convert 127 pounds to kilograms.

Solution :

Weight of adolescent = 127 pounds

We are supposed to find the weight in kilograms.

1 pound = 0.453592 kilograms

127 pounds = 0.453592 \times 127 kilograms

127 pounds = 57.606184 kilograms

Hence 127 pounds in kilograms is 57.606184 kilograms

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Answer:

3.15-1.28\frac{0.38}{\sqrt{11}}=3.003    

3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297    

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=3.15 represent the sample mean

\mu population mean (variable of interest)

\sigma=0.38 represent the population standard deviation

n=11 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.80 or 80%, the value of \alpha=0.2 and \alpha/2 =0.1, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NOR.INV(0.1,0,1)".And we see that z_{\alpha/2}=1.28

Now we have everything in order to replace into formula (1):

3.15-1.28\frac{0.38}{\sqrt{11}}=3.003    

3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297    

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147    

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