Answer:
The p-value is 2.1%.
Step-by-step explanation:
We are given that a study is done to see if the average age a "child" moves permanently out of his parents' home in the United States is at most 23. 43 U.S. Adults were surveyed.
The sample average age was 24.2 with a standard deviation of 3.7.
Let
= <em>true average age a "child" moves permanently out of his parents' home in the United States.</em>
So, Null Hypothesis,
:
23 {means that the average age a "child" moves permanently out of his parents' home in the United States is at most 23}
Alternate Hypothesis,
:
> 23 {means that the average age a "child" moves permanently out of his parents' home in the United States is greater than 23}
The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about population standard deviation;
T.S. =
~ 
where,
= sample average age = 24.2
s = sample standard deviation =3.7
n = sample of U.S. Adults = 43
So, <u><em>the test statistics</em></u> =
~ 
= 2.127
The value of t-test statistics is 2.127.
<u>Now, the p-value of the test statistics is given by;</u>
P-value = P(
> 2.127) = 0.021 or 2.1%