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KatRina [158]
1 year ago
9

Write the number as the product of a real number and i

d="TexFormula1" title=" \sqrt{ - 25} = " alt=" \sqrt{ - 25} = " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Aneli [31]1 year ago
3 0

first, consider that 25 = 5^2, and -25 = -1*25 = -1*5^2.

Then, you can write:

\sqrt[]{-25}=\sqrt[]{(-1)(25)}=\sqrt[]{(-1)(5^2)}=5\sqrt[]{-1}=5i

because i = √-1.

Hence, the answer is 5i

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X-5y=55 slope intercept form
Talja [164]

Answer:

y = x/5 -11

Step-by-step explanation:

y = mx + b (slope intercept form)

5y = x-55

y = x/5 -11

4 0
2 years ago
Which numbers have a digit in the ones place that is 1/10 the value of the digit in the tens place
liq [111]

Answer:

4,099  and 5,011

Step-by-step explanation:

This problem can be solved by taking options one by one.

Option (1) : 4,099  

Digit in ones place = 9

The value of the digit in tens place = 90

\dfrac{9}{90}=\dfrac{1}{10}. It is correct.

Option (2) : 4,110

Digit in one places = 0

The value of the digit in tens place = 10

It is incorrect.

Option (3) : 5,909

Digit in one places = 9

The value of the digit in tens place = 0

It is again incorrect.

Option (4) : 5,011

Digit in one places = 1

The value of the digit in tens place = 10

\dfrac{1}{10}. It is correct.

Hence, in option (a) and (d), the he ones place is 1/10 the value of the digit in the tens place.

7 0
3 years ago
I need help please right answers only
yarga [219]

Answer:

-3/2

Step-by-step explanation:

Count up three times and to the left twice. Let me know if you need help with other questions!

7 0
2 years ago
In ∆ABC the angle bisectors drawn from vertices A and B intersect at point D. Find m∠ADB if: m∠C=130°
Zepler [3.9K]

Answer:

  m∠ADB = 155°

Step-by-step explanation:

  m∠ADB = (m∠C)/2 + 90° = 130°/2 + 90°

  m∠ADB = 155°

_____

Reference brainly.com/question/17443119 for the derivation.

3 0
3 years ago
Read 2 more answers
What is the roots of the quadratic equation? 6x^2+5x-4=0
Rama09 [41]

x = \frac{1}{2} or x = - \frac{4}{3}

consider the factors of the product 6 × - 4 = - 24 which sum to the coefficient of the x- term ( + 5)

the factors are + 8 and - 3 ( split the middle term using these factors

6x² - 3x + 8x - 4 = 0 ( factor by grouping )

3x(2x - 1) + 4(2x - 1 ) ( take out common factor of (2x - 1) )

= (2x - 1)(3x + 4) = 0

equate each factor to zero and solve for x

2x - 1 = 0 ⇒ x = \frac{1}{2}

3x + 4 = 0 ⇒ x = - \frac{4}{3}


4 0
3 years ago
Read 2 more answers
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