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1 year ago

9

Write the number as the product of a real number and i

d="TexFormula1" title=" \sqrt{ - 25} = " alt=" \sqrt{ - 25} = " align="absmiddle" class="latex-formula">

1 answer:

Aneli [31]1 year ago

3 0

first, consider that 25 = 5^2, and -25 = -1*25 = -1*5^2.

Then, you can write:

$\sqrt[]{-25}=\sqrt[]{(-1)(25)}=\sqrt[]{(-1)(5^2)}=5\sqrt[]{-1}=5i$

because i = √-1.

Hence, the answer is 5i

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One of the tallest living men has a height of 236 cm. One of the tallest living women is 224 cm tall. Heights of men have a mean

Roman55 [17]

Answer:

A. The woman is relatively taller because the z score for her height is greater than the z score for the man's height.

Step-by-step explanation:

Whoever has the highest z-score, is taller relative to the population of the same gender.

The z-score of a value X in a set with mean $\mu$ and standard deviation $/sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

Solution:

Heights of men have a mean of 170 cm and a standard deviation of 6 cm. One of the tallest living men has a height of 236 cm. So the z-score of his height is:

$Z = \frac{X - \mu}{\sigma} = \frac{236-170}{6} = 11$

Heights of women have a mean of 161 cm and a standard deviation of 5 cm.

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$Z = \frac{X - \mu}{\sigma} = \frac{224-161}{5} = 12.6$

The women has a higher z-score, so she is relatively taller.

The correct answer is A

3 0

4 years ago

When chad had one cat he needed to serve 1/5 of a can of cat food each day. Now that chad adopted a second cat he needs to serve

Akimi4 [234]

Answer:

$5\frac{3}{10}$ cans extra food is needed to feed the second cat.

Step-by-step explanation:

Given:

When chad had one cat he needed to serve 1/5 of a can of cat food each day. Now that chad adopted a second cat he needs to serve a total of 11/2 cans each day.

Now, to find the extra food is needed to feed the second cat.

Food needed for one cat = $\frac{1}{5}\ of\ can.$

Food needed for both one and second cat needed = $\frac{11}{2}\ =5\frac{1}{2}\ cans.$

Now, extra food needed to feed the second cat:

<u><em>Food needed for both one and second cat needed - food needed for one cat.</em></u>

<u><em /></u> $\frac{11}{2} -\frac{1}{5}\\\\=\frac{55-2}{10} \\\\=\frac{53}{10}$ <u><em /></u>

<u><em /></u> $=5\frac{3}{10}\ cans.$ <u><em /></u>

Therefore, $5\frac{3}{10}\ cans$ extra food is needed to feed the second cat.

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3 years ago

(9y+5x) (9y-5x)<br> Simplify your answer.

Alex777 [14]

Answer:

$81 {y}^{2} - 25 {x}^{2}$

Step-by-step explanation:

$(9y+5x) (9y-5x) \\ \\ = {(9y)}^{2} - {(5x)}^{2} \\ \\ = 81 {y}^{2} - 25 {x}^{2}$

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B. <span> 32.6 ft/s and approximately 0.03 s/ft
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Answer:

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