m_6 + m_8 = 180º because they form a straight line.
So, (2x-5) + (x+5) = 180
3x = 180
x = 60
So, m_115º (2•60 - 5 = 115)
Also, because the two lines are parallel m_6 = m_3 by alternate interior angles.
So, m_3 = 115º
What's the question or what you are trying to find
Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
