$6x-8y\geq-24\qquad\text{subtract 6x from both sides}\\\\-8y\geq-6x-24\qquad\text{change the signs}\\\\8y\geq6x+24\qquad\text{divide both sides by 8}\\\\y\geq\dfrac{6}{8}x+3\\\\\boxed{y\geq\dfrac{3}{4}x+3}$

3 0

2 years ago

What are the zeros of the polynomial function? f(x)=x2−12x+20 Enter your answers in the boxes. The zeros of f(x) are and

Schach [20]

$f(x)=x^{2} -12x+20$
$f(x)=0$
x $x^{2} -12x+20=0$
Factoring:
$(x-2)(x-10)=0$
Two possible soolutions:

$x-2=0 [tex]x=2$

$x-10=0$
$x=10$

The zeros of the polynomial function are x=2 and x=10

5 0

2 years ago

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