How many full cases and additional items are needed to fulfill the order 80 6

Mathematics

1 answer:

Paha777 [63]2 years ago

8 0

The number of cases is 13 and the additional units are 2 if the 80 units needed 6 units per case.

<h3>What is a fraction?</h3>

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

The question is incomplete.

The complete question is:

80 units needed 6 units per case. What are the number of cases and the number of additional units?

Total number of units = 80 units

6 units per case

Number of case = 80/6 = 13.33 ≈ 13

Total units if the number of cases = 13

= 13×6

= 78

Additional units = 80 - 78 = 2 units

Thus, the number of cases is 13 and the additional units are 2 if the 80 units needed 6 units per case.

Learn more about the fraction here:

brainly.com/question/1301963

#SPJ1

You might be interested in

You bought 4.6 meters of fabric that cost $3.57 per meter . what was her total cost

choli [55]

4.6 meters at 3.57 per meter = (4.6 x 3.57) = $ 16.42

4 0

4 years ago

Read 2 more answers

There are 6 blue marbles, 3 red marbles, and 5 yellow marbles in a bag. What is the probability of selecting a blue or red marbl

STALIN [3.7K]

8.5 and the thing is 5/2

5 0

3 years ago

What is the simplified form of the following expression? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0 2

finlep [7]

To solve such questions we need to know more about expression.

<h2 /><h2>Expression </h2>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations that are formed according to rules which are dependent on the context.

<h2 /><h2 /><h2>Given to us,</h2>

$2\sqrt[4]{16x}-2\sqrt[4]{2y}+3\sqrt[4]{81x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-16\sqrt[4]{2y}+13\sqrt[4]{4}-10\sqrt[4]{2y}+35\sqrt[4]{x}-18\sqrt[4]{2y}$

rearranging we get,

$=2\sqrt[4]{16x}+3\sqrt[4]{81x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{4}+35\sqrt[4]{x}-2\sqrt[4]{2y}-4\sqrt[4]{32y}-4\sqrt[4]{32y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}$

we know that,

$\sqrt[4]{81}=3\\\sqrt[4]{16}=2\\\sqrt[4]{32}=2\sqrt[4]{2}\\$

therefore,

$=4\sqrt[4]{x}+9\sqrt[4]{x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{x}+35\sqrt[4]{x}-2\sqrt[4]{2y}-8\sqrt[4]{2y}-8\sqrt[4]{2y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}$