c.y+3=f(x) and 0+3 therefore x=3
Answer:
∂u/∂xi = i·cos(sn)
Step-by-step explanation:
For u = sin(v), the partial derivative of u with respect to xi is ...
∂u/∂xi = cos(v)·∂v/xi
In this case, v=sn, and ∂sn/∂xi = i, so the derivatives of interest are ...
∂u/∂xi = i·cos(sn)
Answer:
y = x^2 - 4
Step-by-step explanation:
The vertex of a parabola is exactly halfway between the focus and the directrix. If the focus is at (0, -6) and the directrix is the line y = -2, then we do this to locate the vertex: Draw a vertical line through (0, -6) also crossing the line y = -2. The y value halfway between y = -6 and y = -2 is y = -4, and the vertex is thus (0, -4).
Using the vertex method, write out the equation of this parabola, starting with the general form y - k = (x-h)^2, where (h, k) is the vertex. Here h = 0 and k = -4
We get: y + 4 = (x - 0)^2, or y + 4 = x^2, or y = x^2 - 4. As a check, let x = 0; y = -4, which is the y-coordinate of the vertex.
