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2 years ago

The graph of g(x) is the result of translating the graph of f(x) = 3 ^ x six units to the rightWhat is the equation of g(x)

Mathematics

1 answer:

Westkost [7]2 years ago

4 0

Answer: $g(x) = 3^{x-6}$

Step-by-step explanation:

Think about it like doing

x - 6 = 0

x = 6

That is how you know that it will be shifted 6 units right (how you can tell the difference between right and left shift)

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Suppose that a box contains r red balls and w white balls. Suppose also that balls are drawn from the box one at a time, at rand

dybincka [34]

Answer: Part a) $P(a)=\frac{1}{\binom{r+w}{r}}$

part b) $P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}$

Step-by-step explanation:

The probability is calculated as follows:

We have proability of any event E = $P(E)=\frac{Favourablecases}{TotalCases}$

For part a)

Probability that a red ball is drawn in first attempt = $P(E_{1})=\frac{r}{r+w}$

Probability that a red ball is drawn in second attempt= $P(E_{2})=\frac{r-1}{r+w-1}$

Probability that a red ball is drawn in third attempt = $P(E_{3})=\frac{r-2}{r+w-1}$

Generalising this result

Probability that a red ball is drawn in [tex}i^{th}[/tex] attempt = $P(E_{i})=\frac{r-i}{r+w-i}$

Thus the probability that events $E_{1},E_{2}....E_{i}$ occur in succession is

$P(E)=P(E_{1})\times P(E_{2})\times P(E_{3})\times ...$

Thus $P(E)$ = $\frac{r}{r+w}\times \frac{r-1}{r+w-1}\times \frac{r-2}{r+w-2}\times ...\times \frac{1}{w}\\\\P(E)=\frac{r!}{(r+w)!}\times (w-1)!$

Thus our probability becomes

$P(E)=\frac{1}{\binom{r+w}{r}}$

Part b)

The event " r red balls are drawn before 2 whites are drawn" can happen in 2 ways

1) 'r' red balls are drawn before 2 white balls are drawn with probability same as calculated for part a.

2) exactly 1 white ball is drawn in between 'r' draws then a red ball again at $(r+1)^{th}$ draw

We have to calculate probability of part 2 as we have already calculated probability of part 1.

For part 2 we have to figure out how many ways are there to draw a white ball among (r) red balls which is obtained by permutations of 1 white ball among (r) red balls which equals $\binom{r}{r-1}$

Thus the probability becomes $P(E_i)=\frac{\binom{r}{r-1}}{\binom{r+w}{r}}=\frac{r}{\binom{r+w}{r}}$

Thus required probability of case b becomes $P(E)+ P(E_{i})$

= $P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}\\\\$

7 0

4 years ago

Somebody help me finish this please

Sauron [17]

x^2 = -25

there is a solution if you know imaginary numbers

if you do not stop now and say no solution

else

take the square root

x = sqrt (-25)

x =sqrt(-1) sqrt(25)

x=+- 5i

x = 5i, -5i

x^2 =18

take the square root of each side

x =+-sqrt(18)

x=+- sqrt(9)sqrt(2)

x=+- 3sqrt(2)

x=3sqrt(2), -3sqrt(2)

4 0

4 years ago

Determine the level of measurement of the data set. (nominal, ordinal,

nevsk [136]

Answer:

Step-by-step explanation:

6 0

3 years ago

Can you help me solve this?

Natalka [10]

Answer:

first one is rational, second is also rational, third is rational, fourth is rational, and fifth is irrational.

Step-by-step explanation:

Rational numbers are numbers that can be expressed as a fraction or part of a whole number. (examples: -7, 2/3, 3.75) Irrational numbers are numbers that cannot be expressed as a fraction or ratio of two integers. The reason why $\sqrt{12}$ is an irrational number is bc it's not a perfect square while $\sqrt{49}$ equals to 7 and is a perfect square.

6 0

3 years ago

Read 2 more answers

Rose walks 2 2/3 km in three-fifths of an hour. If her speed remains unchanged, how many kilometres can she walk in one and thre

mr_godi [17]

Answer:

Distance = 7 7/9 Km

Step-by-step explanation:

Given the following data;

Distance = 2⅔ = 8/3 Km

Time = ⅗ hour

First of all, we would find her speed;

Speed = distance/time

Speed = (8/3)/(3/5)

Speed = 8/3 * 5/3

Speed = 40/9 km/h

Next, we would find the distance covered when time = 1¾ hours

Distance = speed * time

Distance = 40/9 * 1¾

Distance = 40/9 * 7/4

Distance = 10/9 * 7

Distance = 70/9

Distance = 7 7/9 Km

7 0

3 years ago