find the dimensions of a rectangle whose width is 5 miles less than its length and whose area is 66 square miles
1 answer:
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Answer:
56.39 nm
Step-by-step explanation:
In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,
where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...
Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.
In order to have its longest constructive reflection at the red end (700 nm)
Here we take m=0.
Similarly for the constructive reflection at the blue end (400 nm)
Hence the thickness difference should be
The perimeter of a shape is the sum of its side lengths.
<em>Joshua miscalculated the third length of the triangle</em>
First, we calculate the third length (x) of the triangle.
Because the triangle is right-angled, we can make use of Pythagoras.
So we have:
Take square roots of both sides
The other shape in the figure is a square.
So, the perimeter (P) is
---- i.e. the sum of the visible lengths
So, we have:
Evaluate like terms:
Hence, Joshua's error is that:
<em>He miscalculated the third length of the triangle</em>
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