3 years ago

find the dimensions of a rectangle whose width is 5 miles less than its length and whose area is 66 square miles

1 answer:

4 0

A = l * w
66 = l * (l - 5)
66 = $l^{2}$ -5l
0 = $l^{2}$ -5l - 66

l = 11 or 6 check which works.

A = 11 * 6, which fits.

length = 11 miles
width = 5 miles

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