Question

find the dimensions of a rectangle whose width is 5 miles less than its length and whose area is 66 square miles

Answer 1

A = l * w
66 = l * (l - 5)
66 = $l^{2}$-5l
0 = $l^{2}$-5l - 66

l = 11 or 6 check which works.

A = 11 * 6, which fits.

length = 11 miles
width = 5 miles