Well, if 1 mile = 1.6 kilometers and he's traveling at 18mph, then do 18 x 1.6 which = 28.8.
So, this is his current speed in kph
3 x 28.8 = 86.4
They will have traveled 86.4 kilometers
(I haven't worked with this kind of math in a while so correct me if I'm wrong!)
Answer:
19
Step-by-step explanation:

For Question 1:
angle CAB, angle ABC, angle BCA
Question 2: angle BCD
A = 4πr² Divide both sides by 4π
A / 4π = r² Find the square root of both sides
√(A / 4π) = √(r²) Cancel out the square with the square root
√(A / 4π) = r Switch the sides to make it easier to read
r = √(A / 4π)
Draw a right triangle.


Arctangent (tan^-1) can be used to find theta.
