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3 years ago

What is the absolute value of -1.8?

Mathematics

2 answers:

lisabon 2012 [21]3 years ago

5 0

Answer:

1.8

Step-by-step explanation:

IgorC [24]3 years ago

3 0

Answer:

1.8

Step-by-step explanation:

abs -1.8 = 1.8

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Segments AB, DC and Ec intersect at point C. Angel DCE measures 148. Find the value of x.

Anna71 [15]

The image is attached.

Answer:

x = 16°

Step-by-step explanation:

Segment AB, segment DC and segment EC all intersect at point C.

Here, we are told angle DCE measures 148°.

This is a semi-circle, and the total angle of a semi-circle is 180°.

Which means, x+x+148 = 180

Solving for x, we have:

x+x+148 = 180

2x + 148 = 180

2x = 180 - 148

2x = 32

$x = \frac{32}{2}$

x = 16°

The value of x is 16°

6 0

3 years ago

In Nathan's baseball card.Collection 58% of the cards are players from the national league. He has 702 baseball cards. About how

Sergeu [11.5K]

He has 407 players more in national league than in American league

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3 years ago

Please help. Thank you

love history [14]

Answer:

The length of side x is $x = \sqrt{6}$

Step-by-step explanation:

Pythagorean Theorem:

In a right triangle, with sides a and b, and hypothenuse h, we have that:

$a^2 + b^2 = h^2$

In this question:

The vertical line on the sides means that both are equal, that is, measuring x, so $a = b = x$ .

Hypothenuse is the square root of 12. So $h = \sqrt{12}$

$x^2 + x^2 = (\sqrt{12})^2$

$2x^2 = 12$

$x^2 = \frac{12}{2}$

$x^2 = 6$

$x = \sqrt{6}$

The length of side x is $x = \sqrt{6}$

8 0

2 years ago

Choose the solutions to the quadratic equation

WITCHER [35]

29 I think but iam not sure if it’s right

4 0

3 years ago

Use matrices and elementary row to solve the following system:

LiRa [457]

I assume the first equation is supposed to be

$5x-3y+2z=13$

and not

$5x-3x+2x=4x=13$

As an augmented matrix, this system is given by

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]$

Multiply through row 3 by 1/2:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]$

Add -1(row 2) to row 3:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]$

Multiply through row 3 by 1/5:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]$

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

$\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Add -3(row 2) to row 1:

$\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Multiply through row 1 by -1:

$\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Add -2(row 1) to row 2:

$\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]$

Multipy through row 2 by -1:

$\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]$

The solution to the system is then

$\boxed{x=1,y=-2,z=1}$

5 0

3 years ago