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Kruka [31]
2 years ago
8

Sine is opposite divided by hypotenuse. So the sine of an angle times the hypotenuse is the length of the opposite side. What is

the length of the side opposite a 30 degree angle for a right triangle with a hypotenuse of 20 meters?​
Mathematics
1 answer:
valkas [14]2 years ago
7 0

Answer:

10 m

Step-by-step explanation:

opposite = sin30° × 20 = \frac{1}{2} × 20 = 10 m

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Verify sin2θ/1+cos2θ =tanθ
Andrej [43]

Answer:

LHS.= Sin 2x /( 1 + cos2x )

We have , sin 2x = 2 sinx•cosx

And. cos2x = 2cos^2 x - 1

i.e . 1+ cosx 2x = 2cos^2x

Putting the above results in the LHSwe get,

Sin2x/ ( 1+ cos2x ) =2 sinx•cosx/2cos^2x

=sinx / cosx

= Tanx

.•. sin2x/(1 + cos2x)= tanx

Step-by-step explanation:

4 0
3 years ago
Excel - How to graph different APRs using one formula for an excel beginner? Image Attached
Levart [38]

Answer:

Please see the attachments. For reasons I cannot fathom, the Brainly censor seems to think there are unapproved words contained in this text, so I cannot post it as text. Among other things, that means you probably will not be able to copy and paste the formulas into your spreadsheet—you will have to type them.

I apologize if you are offended by any of the words contained in this answer. I hope you will take them in the intended context—a math problem about the use of Excel.

3 0
3 years ago
Express the volume of the box as a<br>polynomial in the variable x
Whitepunk [10]

The volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)

<h3>How to determine the volume?</h3>

The complete question is added as an attachment

From the attached image, we have:

Length = 12 - 2x

Width = 7 - 2x

Height = x

The volume is calculated as:

Volume = Length * Width * Height

Substitute the known values in the above equation

Volume = (12 - 2x) * (7 - 2x) * x

This gives

Volume = x(12 - 2x)(7 - 2x)

Hence, the volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)

Read more about polynomial at:

brainly.com/question/4142886

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7 0
2 years ago
Find all the missing elements.
Montano1993 [528]

Answer:

b=30

a=120

c=50 these is how I figure it out

6 0
3 years ago
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D3<br> Find two numbers between 100 and<br> 150 that have a HCF of 22.
vesna_86 [32]

The first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132

<h3>Highest common factors</h3>

The greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

According to the question, we are to find two numbers between 100 and

150 that have a HCF of 22.

In order to do that we will<u> multiply 22 by the values 5 and 6</u>

First number = 22 * 5 = 10

Second number = 22 * 6 = 132

Hence the first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132

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1 year ago
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