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Sergeeva-Olga [200]
3 years ago
13

1. Suppose you take a coin and flip it 4 times in a row. After each flip you record whether the coin landed heads or tails. What

is the probability you’ll get at least 2 heads?
Mathematics
1 answer:
bekas [8.4K]3 years ago
4 0

Answer:

25%

Step-by-step explanation:

Great question, since a regular coin has two sides one heads and one tails. That gives us a 50% probability of it landing on either side of the coin. Since we would like to know the probability of getting 2 heads in a row, we would need to multiply the probability of the first toss landing on heads with the second toss landing on heads, like so...

\frac{1}{2} *\frac{1}{2} =\frac{1}{4}

So we can see that the probability of us getting two heads in a row is that of \frac{1}{4}[/tex] or 25%.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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ivolga24 [154]

Step-by-step explanation:

1. (-3/2, 1)

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8 0
3 years ago
Read 2 more answers
A quadrilateral has two angles that measure 222° and 81°. The other two angles are in a ratio of 6:13. What are the measures of
hram777 [196]

\sf\huge\underline{\star Solution:-}

\rightarrow <u>Ratio of two angles are 6:13.</u>

So, let the one angle be \sf{6x} and another be \sf{13x.}

As we know that,

Sum of all interior angles of a quadrilateral = \sf\pink{360°.}

So let's sum up the given angles,

\rightarrow \sf{222°+81°+6x+13x \:=\:  360°}

\rightarrow \sf{303+19x \:=\:  360°}

\rightarrow \sf{19x \:=\:  360-303}

\rightarrow \sf{19x \:=\:  57}

\rightarrow \sf{x \:=\:  \frac{19}{57}}

\rightarrow \sf{x \:=\:  3}

Hence, \sf{x \:=\:  3}

So, First angle \sf{= \:6x\: = \:6×3 \:=} \sf\purple{18°.}

Second angle \sf{= \:13x\: = \:13×3 \:=} \sf\purple{39°.}

_________________________________

Hope it helps you:)

3 0
2 years ago
60 + 60 × 0 + 1 = Solve this
belka [17]
61 because you always multiply first 60 x 0= 0 so now we have 60+1 which is 61
5 0
3 years ago
Read 2 more answers
Can anyone help ? I need to answer it for my homework today
Rus_ich [418]
Robot 1- W = 20(3m) W= 60Nm
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5 0
3 years ago
To answer that question
Mars2501 [29]
First, we get ax^2+bx+c. Next, we know that the line of symmetry is -b/2a. Since we know that there is a maximum value, the parabola is facing downwards, so a is negative. For random numbers, we can say that a = -0.5 and b=-10 (b needs to be negative for -b/2a to equal -10), getting -0.5x^2-10x+c. Plugging -10 in for x (since -10 is the middle it is the max), we get -50+100=50. Since the maximum needs to be 5, not 50, we subtract 45 from the answer to get it and therefore make c = -45, getting -0.5x^2-10x-45
5 0
3 years ago
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