1. Suppose you take a coin and flip it 4 times in a row. After each flip you record whether the coin landed heads or tails. What
1 answer:
Answer:
25%
Step-by-step explanation:
Great question, since a regular coin has two sides one heads and one tails. That gives us a 50% probability of it landing on either side of the coin. Since we would like to know the probability of getting 2 heads in a row, we would need to multiply the probability of the first toss landing on heads with the second toss landing on heads, like so...
So we can see that the probability of us getting two heads in a row is that of \frac{1}{4}[/tex] or 25%.
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Answer:
0.4
Step-by-step explanation:
Given:-
- The uniform distribution parameters are as follows:
a = $10,000 b = $15,000
Find:-
Suppose you bid $12,000. What is the probability that your bid will be accepted?
Solution:-
- We will denote a random variable X that defines the bid placed being accepted. The variable X follows a uniform distribution with parameters [a,b].
X ~ U(10,000 , 15,000)
- The probability of $12,000 bid being accepted can be determined by the cdf function of the uniform distribution, while the pmf is as follows:
Pmf = 1 / ( b - a )
Pmf = 1 / ( 15,000 - 10,000 )
Pmf = 1 / ( 5,000 )
Answer:
The given equation will have value less than 100 whenever the value of b is greater than 12.89
Step-by-step explanation:
For the given equation, p(b) = 520 × to have a value less than 100 we can establish inequality as:
p(b) < 100
or, 520 × < 100
or, ×
<
or, <
or, ㏒ ( ) < ㏒ (
)
or, b× ㏒ 0.88 < ㏒ ()
or, < b
or, 12.89 < b
Hence for the equation to have value less than 100, b must be greater than 12.89.