Ask question

Ask question

All categories

1 year ago

7

Find the modulus and the unit vector along the sum of the vectors. - r₁ +r₂ +r3 given that r₁ = 2i+j+4k - r₂ = 3i-2j+7k, r3 = 5i

+ 2j - 3k. 2

1 answer:

bazaltina [42]1 year ago

8 0

j+8k

first -2i+j+4k-3i-2j+7k+5i+2j-3k

You might be interested in

Miss Garner has 69 gold stickers. She wants to give the same number of stickers to each of her 15 students. If she gives away as

Hatshy [7]

Answer: 69/15=4 and remainder 9

Step-by-step explanation: Since 15 x 4 = 60, 15 can't go into 9 so 9 in the leftover

7 0

3 years ago

Read 2 more answers

Dimitry runs 3.1 miles

larisa [96]

Answer:

and?

Step-by-step explanation:

5 0

2 years ago

Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m

GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

$d=\sqrt{\frac{3h}{2} }$

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

$d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)$

For Addison h=85(1/3)

$d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)$

Subtracting both distances we get

$8\sqrt{2}-6\sqrt{2} =2\sqrt{2}$

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0

2 years ago

If f(1)=10 and f(n)=-5f(n-1)-2 then find the value of f(4)

Flura [38]

Answer:

$\large\boxed{f(4)=-1292}$

Step-by-step explanation:

$f(n)=-5f(n-1)-2\\\\f(1)=10\\\\f(2)=-5f(2-1)-2=-5f(1)-2\\\text{put}\ f(1)=10:\\f(2)=-5(10)-2=-50-2=-52\\\\f(3)=-5f(3-1)-2=-5f(2)-2\\\text{put}\ f(2)=-52\\f(3)=-5(-52)-2=260-2=258\\\\f(4)=-5f(4-1)-2=-5f(3)-2\\\text{put}\ f(3)=258\\f(4)=-5(258)-2=-1290-2=-1292$

4 0

3 years ago

Im even worse at this

stira [4]

The first sentence is irrelevant information, you can ignore that!

There are 20 players. Each player paid the <em>same amount. </em>

In total, they payed $500,000.

We need x, the amount a single player pays. x times 20 will give us 500,000. This gives us the equation 20x=500,000

Divide both sides by 20 to isolate the variable.

x=25,000

3 0

3 years ago

Read 2 more answers