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3 years ago

Write an equation for the data in the table. Identify your variables.

Mathematics

1 answer:

Viktor [21]3 years ago

6 0

First find the slope m. slope formula: $\frac{y_{2} - y_{1} }{x_{2} - x_{1} }$

Let's use (0, -20) for x1 and y1; and (2, 10) for x2 and y2

$\frac{10-(-20)}{2-0}$ = $\frac{30}{2}$ = $15$

Now find the y-intercept: the point where the graph crosses the y-axis. The y intercept always has an x value of 0. So -20 is the y-intercept

Use the slope formula $y = mx + b$ . Slope=m, y-intercept = b

y = 15x - 20

y is the money in the bank account in dollars

x is the day

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The system of equations kx-5y = 2, 6x+2y = 7 has no solution, then k =

hoa [83]

Answer:

(d) -15

Step-by-step explanation:

Given system of equations are:

$\begin{cases}kx-5y=2\\\\6x+2y=7\end{cases}$

Since, given system of equations have no solution.

$\therefore \frac{k}{6}=\frac{-5}{2} \neq\frac{2}{7}$

$\implies \frac{k}{6}=\frac{-5}{2}$

$\implies k=\frac{6(-5)}{2}$

$\implies k=\frac{-30}{2}$

$\implies k=-15$

6 0

3 years ago

10 Points shown in my point board Helppppp

Daniel [21]

The best answer is "We can expect 135 of the grandparents to spend less than 2 hours a day online" because about 54% of all people said they spend >2 hours online everyday, and 54% of 250 is 135.

Hope this helps!

7 0

3 years ago

Read 2 more answers

Write an expression to match the words "three times the sum of 8 and 4"

leva [86]

The expression would be:
3*8+4
3 times 8 plus 4

7 0

4 years ago

Read 2 more answers

1. Quadrilateral ABCD has vertices A(-1, 1), B(2, 3), C(6, 0) and D(3, -2). Determine using coordinate geometry whether or not t

deff fn [24]

Answer:

The Conclusion is

Diagonals AC and BD,

a. Bisect each other

b. Not Congruent

c. Not Perpendicular

Step-by-step explanation:

Given:

[]ABCD is Quadrilateral having Vertices as

A(-1, 1),

B(2, 3),

C(6, 0) and

D(3, -2).

So the Diagonal are AC and BD

To Check

The diagonals AC and BD

a. Bisect each other. B. Are congruent. C. Are perpendicular.

Solution:

For a. Bisect each other

We will use Mid Point Formula,

If The mid point of diagonals AC and BD are Same Then

Diagonal, Bisect each other,

For mid point of AC

$Mid\ point(AC)=(\dfrac{x_{1}+x_{2} }{2},\dfrac{y_{1}+y_{2} }{2})$

Substituting the coordinates of A and C we get

$Mid\ point(AC)=(\dfrac{-1+6}{2},\dfrac{1+0}{2})=(\dfrac{5}{2},\dfrac{1}{2})$

Similarly, For mid point of BD

Substituting the coordinates of B and D we get

$Mid\ point(BD)=(\dfrac{2+3}{2},\dfrac{3-2}{2})=(\dfrac{5}{2},\dfrac{1}{2})$

Therefore The Mid point of diagonals AC and BD are Same

Hence Diagonals,

a. Bisect each other

B. Are congruent

For Diagonals to be Congruent We use Distance Formula

For Diagonal AC

$l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting A and C we get

$l(AC) = \sqrt{((6-(-1))^{2}+(0-1)^{2} )}=\sqrt{(49+1)}=\sqrt{50}$

Similarly ,For Diagonal BD

Substituting Band D we get

$l(BD) = \sqrt{((3-2))^{2}+(-2-3)^{2} )}=\sqrt{(1+25)}=\sqrt{26}$

Therefore Diagonals Not Congruent

For C. Are perpendicular.

For Diagonals to be perpendicular we need to have the Product of slopes must be - 1

For Slope we have

$Slope(AC)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Substituting A and C we get

$Slope(AC)=\dfrac{0-1}{6--1}\\\\Slope(AC)=\dfrac{-1}{7}$

Similarly, for BD we have

$Slope(BD)=\dfrac{-2-3}{3-2}\\\\Slope(BD)=\dfrac{-5}{1}$

The Product of slope is not -1

Hence Diagonals are Not Perpendicular.

6 0

4 years ago

Whats 3.24 X 10^-5 in standard form?

11111nata11111 [884]

Answer:

3.24 × 10 ^ -5

Step-by-step explanation:

3.24 × 10 ^ -5 is already a standard form...

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3 years ago