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1 year ago

What is 1+1? 10 point if u get it right.

Mathematics

2 answers:

kap26 [50]1 year ago

5 0

Answer:

Step-by-step explanation:

duh add 1 and 1 merge it together to get 11

max2010maxim [7]1 year ago

4 0

that's a hard question imma go with 2 though

Step-by-step explanation:

for this problem let's let x=1 and y also =1 so x+y=2 hope this helps

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The head librarian at a public library releases a report. The report states that visitors to the library want the library to ope

pogonyaev

Answer:

Step-by-step explanation:

The question is not biased. It doesn't push the participants to answer one way or another.

However, the sample is biased. It does not represent the population.

The first and fourth options are correct.

5 0

2 years ago

Simplificar A=4x2-6x2+7x2-20x2+19x2

maks197457 [2]

Answer:

4x²

Step-by-step explanation:

Your equation is 4x² - 6x² + 7x² - 20x² + 19x².

Since they all have the same variable, simply combine them all to find your answer.

4x² - 6x² + 7x² - 20x² + 19x²

-2x² + 7x² - 20x² + 19x²

5x² - 20x² + 19x²

-15x² + 19x²

4x²

7 0

2 years ago

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

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3 years ago

One student is selected at random from a group of 12 freshman, 16 sophomores,

ycow [4]

A because it’s less likely to be a freshman

4 0

2 years ago

The outside world recoils in fear

Alexeev081 [22]

Answer:

liar! only 5 points! SU LITERALLY IDC REMOVE UR ANSWER OR ELSE THUG

Step-by-step explanation:

3 0

2 years ago

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