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Paraphin [41]
3 years ago
6

What single transformation was applied to triangle AAA to get triangle BBB?

Mathematics
1 answer:
UkoKoshka [18]3 years ago
4 0
I assume c, because usually to get to the opposite you reflect the line or figure on the x axis
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4x8 i know the anwser im just tryna see something
Umnica [9.8K]

Answer:

32

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
The description for a certain brand of house paint claims a coverage of 460 ft2/gal. (a) express this quantity in square meters
Angelina_Jolie [31]

Given 460 ft^2/gal

a) convert it into m^2/l

=> It means ft^2 -> m^2 and gal -> l

1 ft = 0.3048 m

1 ft^2 = 0.092903 m^2

1 gal = 3.78541 l

460ft^2= [tex]460\frac{ft^2}{gal} = \frac{42.7354m^2}{3.78541l} = 11.2895m^2/l m^2[/tex].

b.  11.2895\frac{m^{2} }{l} *1000\frac{l}{m^3} =11289.5 m^{-1}

c.Given=  460\frac{ft^2}{gal}

To find inverse, divide it by 1.

Inverse- \frac{1}{460} \frac{gal}{ft^2}




6 0
3 years ago
The area of a trapezoid is 30 cm. If
Arisa [49]

The height of the trapezoid is 2 cm

7 0
3 years ago
. A segment has a midpoint at (2, -7) and an endpoint at (8, -5). What are the coordinates of the other endpoint?
Sliva [168]
Ok, you can refer to the midpoint formula to find the endpoint.  Here goes...


MP=(2,-7) and EP=(8,-5)
Let x represent the missing endpoint.
(8+x)/2=2      NOTE: =2 represents first number of MP and the representation of number 8 is self explanatory.  You have two endpoints but need to identify the other endpoint so you divide by 2.  Then, multiply by two on both sides.
2(8+x)/2 = 2*2
16+x/2=4 do the next step (simplify) on the left side of equation 16x/2=8
Now, subtract 4-8=-4  So, the x coordinated of the missing endpoint is -4.


4 0
3 years ago
Read 2 more answers
Need help with the blanks
Crazy boy [7]
Answers: 
33. Angle R is 68 degrees
35. The fraction 21/2 or the decimal 10.5
36. Triangle ACG
37. Segment AB
38. The values are x = 6; y = 2
40. The value of x is x = 29
41. C) 108 degrees
42. The value of x is x = 70
43. The segment WY is 24 units long
------------------------------------------------------
Work Shown:
Problem 33) 
RS = ST, means that the vertex angle is at angle S
Angle S = 44
Angle R = x, angle T = x are the base angles
R+S+T = 180
x+44+x = 180
2x+44 = 180
2x+44-44 = 180-44
2x = 136
2x/2 = 136/2
x = 68
So angle R is 68 degrees
-----------------
Problem 35) 
Angle A = angle H
Angle B = angle I
Angle C = angle J
A = 97
B = 4x+4
C = J = 37
A+B+C = 180
97+4x+4+37 = 180
4x+138 = 180
4x+138-138 = 180-138
4x = 42
4x/4 = 42/4
x = 21/2
x = 10.5
-----------------
Problem 36) 
GD is the median of triangle ACG. It stretches from the vertex G to point D. Point D is the midpoint of segment AC
-----------------
Problem 37)
Segment AB is an altitude of triangle ACG. It is perpendicular to line CG (extend out segment CG) and it goes through vertex A.
-----------------
Problem 38) 
triangle LMN = triangle PQR
LM = PQ
MN = QR
LN = PR
Since LM = PQ, we can say 2x+3 = 5x-15. Let's solve for x
2x+3 = 5x-15
2x-5x = -15-3
-3x = -18
x = -18/(-3)
x = 6
Similarly, MN = QR, so 9 = 3y+3
Solve for y
9 = 3y+3
3y+3 = 9
3y+3-3 = 9-3
3y = 6
3y/3 = 6/3
y = 2
-----------------
Problem 40) 
The remote interior angles (2x and 21) add up to the exterior angle (3x-8)
2x+21 = 3x-8
2x-3x = -8-21
-x = -29
x = 29
-----------------
Problem 41) 
For any quadrilateral, the four angles always add to 360 degrees
J+K+L+M = 360
3x+45+2x+45 = 360
5x+90 = 360
5x+90-90 = 360-90
5x = 270
5x/5 = 270/5
x = 54
Use this to find L
L = 2x
L = 2*54
L = 108
-----------------
Problem 42) 
The adjacent or consecutive angles are supplementary. They add to 180 degrees
K+N = 180
2x+40 = 180
2x+40-40 = 180-40
2x = 140
2x/2 = 140/2
x = 70
-----------------
Problem 43) 
All sides of the rhombus are congruent, so WX = WZ.
Triangle WPZ is a right triangle (right angle at point P).
Use the pythagorean theorem to find PW
a^2+b^2 = c^2
(PW)^2+(PZ)^2 = (WZ)^2
(PW)^2+256 = 400
(PW)^2+256-256 = 400-256
(PW)^2 = 144
PW = sqrt(144)
PW = 12
WY = 2*PW
WY = 2*12
WY = 24
3 0
3 years ago
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