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lubasha [3.4K]
2 years ago
14

CosA/secA+sinA/cosecA=1 ​

Mathematics
1 answer:
Alona [7]2 years ago
4 0

Step-by-step explanation:

please mark me as brainlest

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Simplify<br> ( 3w + 7 ) + ( 2w + 5)
valentina_108 [34]

Answer:

The answer is 5w+12.

Step-by-step explanation:

Combine like terms:

(3w+7)+(2w+5)

5w+12

6 0
3 years ago
Can someone help me please
Radda [10]

B is correct, and D is correct.

that is the answer to that question. Ive already done this question before and I got it right everytime

4 0
3 years ago
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BC = 36; D = 15. What is the value of BD - AC.<br> B<br> A<br> BD - AC =
Snezhnost [94]

Answer:

BD - AC = 0

Step-by-step explanation:

Given that:

BC = 36 , CD = 15 and BD = x

As these are forming right angled triangle,

Using Pythagorean theorem,

(BD)^2+(CD)^2=x^2\\(36)^2+(15)^2 = x^2\\1296 + 225 = x^2\\1521 = x^2\\

Taking square root on both sides

\sqrt{x^2}=\sqrt{1521}\\x=39

As the given shape is rectangular, the sides parallel to each other will have same values.

AB = 15 , AD = 36 and AC = x

(15)^2+(36)^2 = x^2 \\225 + 1296 = x^2 \\1521 = x^2 \\x = 39

Now,

BD - AC = 39 - 39 = 0

Hence,

BD - AC = 0

5 0
3 years ago
A) how many ways are there to choose 10 players to take the field?
Kruka [31]

A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.

B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4. (13−10)! 3!

C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =

10! 3!

9!1! 1!2! 10! 3!

8!2! 2!1! 10! 3!

7!3! 3!0!

= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =

= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =

= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285 1·2·3

<span>possible choices.</span><span> 
</span>

  


5 0
3 years ago
The sum of three consecutive integers is 267. What is the largest integer? (1 point)
Anna11 [10]

Answer:

2=1

Step-by-step explanation:

6 0
3 years ago
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