Hi! I don’t know what any of this means but I hope you have an amazing day and I hope god/allah/etc. blesses you :)
sorry I couldn’t answer
Answer:
$6,400
Step-by-step explanation:
9100-1100
8000
8000×1/5
$1600
8000-1600
$6,400
5A + 7 = 3A + 7 + 2A
We need to solve for A.
3A + 7 + 2A = 3A + 2A + 7 = 5A + 7 (We can add 3A and 2A because it's the same variable, so we add the coefficients)
5A + 7 = 3A + 7 + 2A
5A + 7 = 5A + 7
5A + 7 is always equal to 5A + 7 because it's the same equation. So the equation got infinitely many solutions.
Answer:
Well the whole answer is 10.246950 smth smth but I don’t have the multiple choices so your gonna have to round yourself
Step-by-step explanation:
Okay so you have a weigh of 8 and a diagonal of 13.
If you look, theres a triangle there. One side has 8 and the diagonal that was cut forms a 13. So we have a leg and a hypotnuse. To find the other leg (length) just follow the Pythagorean theroum and solve for b or a.
Pythagorean theroum: a^2+b^2=c^2
Now subsitute c for 13 since its the hypotnuse and a or b as 8 but only one.
In this case I’m substituting a for 8.
8^2+b^2=13^2
Solve the squares
64+b^2= 169
Isolate the b
b^2=105
Now square root 105
√105 will give the answer above on a normal calculator but if you have to round, I don’t know what place but you can round.
Answer:

Step-by-step explanation:
We are given;
- The equation of a line 6x-2y=4+6y
- A point (8, -16)
We are required to determine the equation of a line parallel to the given line and passing through the given point.
- One way we can determine the equation of a line is when we are given its slope and a point where it is passing through,
First we get the slope of the line from the equation given;
- We write the equation in the form y = mx + c, where m is the slope
That is;
6x-2y=4+6y
6y + 2y = 6x-4
8y = 6x -4
We get, y = 3/4 x - 4
Therefore, the slope, m₁ = 3/4
But; for parallel lines m₁=m₂
Therefore, the slope of the line in question, m₂ = 3/4
To get the equation of the line;
We take a point (x, y) and the point (8, -16) together with the slope;
That is;


Thus, the equation required is 