Find the solutions to the system

A rectangle school banner has a length of 44 inches, a perimeter of 156 inches , and an area of 1496 square inches. The cheerlea

Andrej [43]

Based on the lengths, the cheerleaders' banner is scaled down by a factor of 4.

So, 44 ÷ 4 = 11.

For the perimeter, 156 ÷ 4 is 39.

For the area, you have to do A=bh
(Area = base × height)

The base (length) is 11 inches, multiply that by two to get 22 inches which is the amount for both lengths. If the total perimeter is 39, you have to subtract 22 from that to get the remaining inches which is 17.
17÷2= 8.5 inches. The height is 8.5.

Now you can plug them in
A=bh
A=(11)(8.5)
A=93.5 in^2

The final answer is:
Area = 93.5 in^2
Length = 11 in
Perimeter = 39 in

I hope that helps!

7 0

3 years ago

Please answer this!!

Vinvika [58]

Answer:

16

Step-by-step explanation:

if angle c is 45 then angle A is 45 also

Hence AB is equal to BC

8 0

2 years ago

Hannah has a biased coin.

muminat

Look at it this way:

When you flip a coin, the probability of it landing with EITHER side showing
is 100%.

This leads us to the rule ...

The sum of the probabilities of
all possible outcomes is 100%.

For a coin: (probability of heads) plus (probability of tails) = 100%.

That just says: We're 100% sure that the coin will land with either
heads or tails up.

An "honest" coin gets heads 50% of the time and tails the other 50%.

But if the coin is all bent and squashed and has a feather stuck to
one side and a wad of gum on the other side so that it comes up
heads 70% of the time, then the coin isn't 'honest'. But it still has to
land EITHER heads OR tails, so the sum of the probabilities is still 100%.

So the probability of heads is 30%.

7 0

3 years ago

A random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6. A random sample of 17 su

Sladkaya [172]

Answer:

We conclude that there is no difference in potential mean sales per market in Region 1 and 2.

Step-by-step explanation:

We are given that a random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6.

A random sample of 17 supermarkets from Region 2 had a mean sales of 78.3 with a standard deviation of 8.5.

Let $\mu_1$ = mean sales per market in Region 1.

$\mu_2$ = mean sales per market in Region 2.

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2$ = 0 {means that there is no difference in potential mean sales per market in Region 1 and 2}

Alternate Hypothesis, $H_A$ : > $\mu_1-\mu_2\neq$ 0 {means that there is a difference in potential mean sales per market in Region 1 and 2}

The test statistics that will be used here is Two-sample t-test statistics because we don't know about population standard deviations;

T.S. = $\frac{(\bar X_1 -\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+ {\frac{1}{n_2}}} }$ ~ $t__n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean sales in Region 1 = 84

$\bar X_2$ = sample mean sales in Region 2 = 78.3

$s_1$ = sample standard deviation of sales in Region 1 = 6.6

$s_2$ = sample standard deviation of sales in Region 2 = 8.5

$n_1$ = sample of supermarkets from Region 1 = 12

$n_2$ = sample of supermarkets from Region 2 = 17

Also, $s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $s_p=\sqrt{\frac{(12-1)\times 6.6^{2}+(17-1)\times 8.5^{2} }{12+17-2} }$ = 7.782

So, the test statistics = $\frac{(84-78.3)-(0)}{7.782 \times \sqrt{\frac{1}{12}+ {\frac{1}{17}}} }$ ~ $t_2_7$

= 1.943

The value of t-test statistics is 1.943.

Now, at a 0.02 level of significance, the t table gives a critical value of -2.472 and 2.473 at 27 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that there is no difference in potential mean sales per market in Region 1 and 2.

6 0

3 years ago

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

r-ruslan [8.4K]

The first thing you should do is to determine all the zeros, and you will have 7, -11, 2 + 6i, 2 - 6i.
After that you have to subtract and (x) from every each zero that you have above, which means
 $7-x, 

 -11-x, 

2 + 6i-x,

 2 - 6i-x
$
And the last step is to multiply them together, and that's all you need!
 $(7-x)(-11-x)(2 + 6i-x)(2 - 6i-x)$
I am pretty sure that everything hase become clear! Regards.

6 0

3 years ago