Answer:
73.5
Step-by-step explanation:
I assume you are trying to find 4x+23y. To do this, let's plug in 1.5 for x and 3 for y. When we do so, we get 4*1.5 + 23*3 = 6 + 69 = 75. Hope this helps!
Answer:
Tony can buy three games with his savings over two months and Alice can buy six concert tickets.
Step-by-step explanation:
Over two months, Tony has watched a total of 53.6 hours of television (35.4 + 18.2). If he save $2.50 for each hour, we can multiply his total hours by the amount per hour, or 53.6 x 2.50 = $134.00. Since each game that Tony wants to buy costs $35.75, we need to divide his total savings by the cost of each game, or 134/35.75 = 3.75. Since Tony can't buy a portion of the game, the most amount of games he can buy is 3. Alice watched a total of 48.4 hours of television (21.8 + 26.6). If she also saves $2.50 per hour, then her total savings is 2.50 x 48.4 = $121.00. Since her concert tickets are $17.50 a piece, we divide her total savings: 121/17.50 = 6.9. Alice can also not buy a partial ticket, so the total amount she can buy is 6.
Answer:
A.) the SSS Postulate
Step-by-step explanation:
Two sides of each triangle are marked congruent, and the third side is shared by the triangles. Hence, all three sides are congruent, and the SSS Postulate applies.
the parabola has maximum at 9, meaning is a vertical parabola and it opens downwards.
it has a symmetry at x = -5, namely its vertex's x-coordinate is -5.
check the picture below.
so then, we can pretty much tell its vertex is at (-5 , 9), and we also know it passes through (-7, 1)
![\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \leftarrow \textit{using this one}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=9 \end{cases}\implies y=a[x-(-5)]^2+9\implies y=a(x+5)^2+9](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Bparabola%20vertex%20form%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20y%3Da%28x-%20h%29%5E2%2B%20k%5Cqquad%20%5Cleftarrow%20%5Ctextit%7Busing%20this%20one%7D%5C%5C%5C%5C%20x%3Da%28y-%20k%29%5E2%2B%20h%20%5Cend%7Barray%7D%20%5Cqquad%5Cqquad%20vertex~~%28%5Cstackrel%7B%7D%7B%20h%7D%2C%5Cstackrel%7B%7D%7B%20k%7D%29%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20h%3D-5%5C%5C%20k%3D9%20%5Cend%7Bcases%7D%5Cimplies%20y%3Da%5Bx-%28-5%29%5D%5E2%2B9%5Cimplies%20y%3Da%28x%2B5%29%5E2%2B9)
![\bf \textit{we also know that } \begin{cases} x=-7\\ y=1 \end{cases}\implies 1=a(-7+5)^2+9 \\\\\\ -8=a(-2)^2\implies -8=4a\implies \cfrac{-8}{4}=a\implies -2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-2(x+5)^2+9~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bwe%20also%20know%20that%20%7D%20%5Cbegin%7Bcases%7D%20x%3D-7%5C%5C%20y%3D1%20%5Cend%7Bcases%7D%5Cimplies%201%3Da%28-7%2B5%29%5E2%2B9%20%5C%5C%5C%5C%5C%5C%20-8%3Da%28-2%29%5E2%5Cimplies%20-8%3D4a%5Cimplies%20%5Ccfrac%7B-8%7D%7B4%7D%3Da%5Cimplies%20-2%3Da%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20y%3D-2%28x%2B5%29%5E2%2B9~%5Chfill)
Answer:
(x,y) => (x+3, y+4)
Step-by-step explanation:
Given a triangle DEF, D(4,2), E(3,3), F(2,1).
Centroid of the area (and the vertices) equals the mean of the coordinates, namely ( (4+3+2)/3, (2+3+1)/3 ) = (3,2)
To translate (3,2) to (6,6), we need the rule
(x,y) => x+(6-3), y+(6-2), or
(x,y) => (x+3, y+4)
