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nordsb [41]
1 year ago
6

Kyle is creating a frame for a model car. He begins by piecing two rods together, as shown in the diagram. Justify why AM = 6.

Mathematics
1 answer:
castortr0y [4]1 year ago
3 0

The length of the door frame for the model car is 12 units and point M is the midpoint which makes AM to 6 units.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

From the diagram attached:

AE = 12

AM = ME = 12/2 = 6 (definition of midpoint)

The length of the door frame for the model car is 12 units and point M is the midpoint which makes AM to 6 units.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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The graph of the function f(x) = (x +2)(x + 6) is shown
dalvyx [7]

The true about the domain and the range of the function is:

The domain is all real numbers, and the range is all real  numbers

greater than or equal to -4 ⇒ 1st answer

Step-by-step explanation:

f(x) = (x + 2)(x + 6) is a quadratic function with 2 factors (x + 2) and (x + 6)

By multiplying its two factors we will find the form of the quadratic function

∵ (x)(x) = x²

∵ (x)(6) = 6x

∵ (2)(x) = 2x

∵ (2)(6) = 12

∴ f(x) = x² + 6x + 2x + 12

- By adding like terms

∴ f(x) = x² + 8x + 12

The quadratic function represented graphically by a parabola

Look to the attached figure

The x-coordinate of the vertex point of the parabola h = \frac{-b}{a}

where b is the coefficient of x and a is the coefficient of x²

∵ f(x) = x² + 8x + 12

∴ a = 1 and b = 8

∴ h = \frac{-8}{2*1}=-4

The y-coordinate of the vertex point is k = f(h)

∵ h = -4

∴ k = f(-4)

∴ k = (-4)² + 8(-4) = 12 = 16 - 32 + 12

∴ k = -4

∴ The vertex point of the parabola is (-4 , -4)

∵ The parabola is opened upward

∴ Its vertex is minimum point

∴ The minimum value of f(x) is y = -4

∵ The domain of the function is the values of x

∵ The range of the function is the values of y corresponding to the

   values of x

∵ x can be any real numbers

∴ x ∈ R, where R is the set of real numbers

∴ The domain of f(x) is all real numbers

∵ The minimum value of f(x) is y = -4

∴ y can be any real number greater than or equal to -4

∴ y ≥ -4

∴ The range is all real number greater than or equal to -4

The true about the domain and the range of the function is:

The domain is all real numbers, and the range is all real  numbers

greater than or equal to -4

Learn more:

You can learn more about quadratic function in brainly.com/question/1332667

#LearnwithBrainly

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I'm just guessing but if you subtract the 1 from 11 and divide by 2 on both sides then T would equal 5
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