Answer:
B(-3,-2), C(-3,-4.5),D(-0.5,-4.5)
Step-by-step explanation:
step 1
Find the length side of the square
we know that the perimeter of square is
where
b is the length side of the square
we have
substitute and solve for b
Divide by 4 both sides
step 2
Find out the coordinates of the other three vertices
Let
A(-0.5,-2) ---> the given coordinates of one vertex
we know that
all of the vertices are located in Quadrant III
so
the other three vertices are located at the left and down of vertex A
coordinate of vertex B located at 2.5 units at left of vertex A
coordinate of vertex C located at 2.5 units at left and 2.5 units down of vertex A
coordinate of vertex D located at 2.5 units down of vertex A
therefore
B(-0.5-2.5,-2) -----> B(-3,-2)
C(-0.5-2.5,-2-2.5) -----> C(-3,-4.5)
D(-0.5,-2-2.5) -----> D(-0.5,-4.5)
see the attached figure to better understand the problem