2 years ago

Find the value of x. (Round to the nearest tenth as needed.)

1 answer:

7 0

Answer:

Hope that answers your question

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Alina [70]

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Step-by-step explanation:

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maks197457 [2]

Answer: $(x^{\frac{2}{7}})(x^{\frac{3}{5}})$

Step-by-step explanation:

If you took the nth root of x, it is the same as raising x to the power of 1/n. Therefore:

$\sqrt[7]{x^{2} } = (x^{2} )^{1/7} = (x^{\frac{2}{7}})\\\sqrt[5]{x^{3} } = (x^{3} )^{1/5} = (x^{\frac{3}{5}})$

And multiply:

$(x^{\frac{2}{7}})(x^{\frac{3}{5}})$

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Alexandra [31]

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Aleks04 [339]

You didn’t put the math problems for us to answer the questions

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2 years ago

Find the value of x. (Round to the nearest tenth as needed.)​