All categories

2 years ago

Solve for x: -24 = 6x 1/4 -4 4 - 1/4

Mathematics

2 answers:

Georgia [21]2 years ago

4 0

Answer:

-4

Step-by-step explanation:

$~~~~~-24 = 6x\\\\\\\implies -\dfrac{24} 6 = \dfrac{6x}6\\\\\\\implies x = -4$

lapo4ka [179]2 years ago

4 0

Given ,

-24 = 6x

=> 6 x = -24

=> x = -24/6

=> x = -4

Hence second option is correct

You might be interested in

A publisher estimates their costs of publishing a book is from $780,000 to $1,040,000. So far, they have spent $624,000. Which c

natulia [17]

The <em><u>correct answer</u></em> is:

156,000 ≤ x ≤ 416,000

Explanation:

The amounts they can spend range from 780,000 to 1,040,000. They have already spent 624,000 and have an unknown amount left to spend. This gives us the inequality

780,000 ≤ 624,000 + x ≤ 1,040,000

To solve this, subtract 624,000 from all 3 sides:

780,000-624,000 ≤ 624000+x-624,000 ≤ 1,040,000-624,000

156,000 ≤ x ≤ 416,000

4 0

3 years ago

Read 2 more answers

What is the expression for the calculation double 5 and then multiply by 3?

Ksivusya [100]

(2 x 5) x 3

will be your answer for the expression

hope this helps

4 0

3 years ago

Each side of a square is increasing at a rate of 3 cm/s. at what rate is the area of the square increasing when the area of the

deff fn [24]

The squares length is increasing by 5.33 cm/ s

3 0

4 years ago

Simplify the following expression.

damaskus [11]

The answer is C, 55x-26
-11x*-5 that is 55x
7*-5=-35
9-35=-26
so the ending expression is 55x-26

5 0

3 years ago

given two terms in a geometric sequence find the 8th term and the recursive formula . a4=-12 and a5=-6

Crazy boy [7]

A geometric sequence is defined by a starting point, $a$ , and a common ratio $r$

The first term is $a$ , and you get every next term by multiplying the previous one by r.

So, our terms are

$\left[\begin{array}{c|c}a_1&a\\a_2&ar\\a_3&ar^2\\a_4&ar^3=-12\\a_5&ar^4=-6\end{array}\right]$

We can see that when we pass from $a_4$ to $a_5$ the number gets halved ( $-12 \mapsto -6$ )

This implies that the common ratio is $r = \frac{1}{2}$

So, the table becomes

$\left[\begin{array}{c|c}a_1&a\\a_2&\frac{1}{2}a\\a_3&\frac{1}{4}a\\a_4&\frac{1}{8}a=-12\\a_5&\frac{1}{16}a=-6\end{array}\right]$

So, we can derive the starting point from either $a_4$ or $a_5$ :

$\dfrac{1}{8}a = -12 \iff a = -12\cdot 8 = -96$

The sequence is thus

$\left[\begin{array}{c|c}a_1&-96\\a_2&-48\\a_3&-24\\a_4&-12\\a_5&-6\\a_6&-3\\\vdots&\vdots\end{array}\right]$

And the recursive formula is

$a_n = -\dfrac{96}{2^{n-1}}$

7 0

4 years ago