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3 years ago

On school days, Kiran walks to school. Here are the lengths of time, in minutes, for Kiran’s walks on 5 school days.

Mathematics

1 answer:

Goryan [66]3 years ago

4 0

Answer:

Step-by-step explanation:

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4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.

nikitadnepr [17]

Answer:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=1$

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0$

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}$

Step-by-step explanation:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))$

$=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})$

$=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1$

2nd

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}$

$=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0$

3th

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))$

$=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}$

What we use?

We use that

$e^{i\pi n}=cos(\pi n)+i sin(\pi n)$

and

$\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}$

6 0

4 years ago

Ez branliest

Mnenie [13.5K]

Answer:

Step-by-step explanation:

4 0

3 years ago

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Ben's teacher wants him to write a 3 digit number that uses the 3 once and a 6 twice. The value of one of the 6 needs to be 1/10

pantera1 [17]

Ben can write the number 366 or 663. There is one three and two sixes. One of each six is greater than the other 6 times 10.

6 0

4 years ago

During a store's opening month, they sold 925 DVD's and 507 Blu-ray discs. Each month thereafter, the number of DVD's sold per m

andreyandreev [35.5K]

The system of equations representing the number of Blue-ray discs and DVD's after t months are:

507 + 26t

925 - 12t

Each month, the number of DVD's sold decreases by 12, this can be modelled as:

number of DVD in opening month - (monthly decrease x number of months)

Number of DVD's in t months = 925 - 12t

Each month, the number of Blue-ray discs sold increases by 26, this can be modelled as:

number of blue-ray discs in opening month + (monthly increase x number of months)

Number of Blue-ray discs in t months = 507 + 26t

To learn more about growth rate, please check: brainly.com/question/18760477

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2 years ago

8.7 to the nearest tenth

Svet_ta [14]

8.7 is already rounded to the nearest tenth

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3 years ago

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