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Ann [662]
3 years ago
14

Can someone explain how you step by step find the slope to questions like this along with the answer? I forget how but I also ca

n’t figure it out and I’d like to know Incase I have more questions like this

Mathematics
1 answer:
Ghella [55]3 years ago
5 0
The formula for graphing is y=mx+b, where m is the slope and b is the slope-intercept (where the line is at x=0). In this case, the slope is 10. Hope this helps and please give branliest!
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HELPPPP FIND THE AREA
GuDViN [60]

you can just split the figure in 2 separate figures and them add the areas:

area rec. 1:

3m×3m= 9m²

area rec. 2:

3m× (2m+3m)

= 3m×5m

=15m²

total area:

9m²+15m²= 24m²

5 0
2 years ago
Read 2 more answers
find the equation of the circle where (-9,4),(-2,5),(-8,-3),(-1,-2) are the vertices of an inscribed square.
solniwko [45]
Check the picture below, so, that'd be the square inscribed in the circle.

so... hmm the diagonals for the square are the diameter of the circle, and keep in mind that the radius of a circle is half the diameter, so let's find the diameter.

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -2}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ -8}}\quad ,&{{ -3}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\stackrel{diameter}{d}=\sqrt{[-8-(-2)]^2+[-3-5]^2}
\\\\\\
d=\sqrt{(-8+2)^2+(-3-5)^2}\implies d=\sqrt{(-6)^2+(-8)^2}
\\\\\\
d=\sqrt{36+64}\implies d=\sqrt{100}\implies d=10

that means the radius r = 5.

now, what's the center?  well, the Midpoint of the diagonals, is really the center of the circle, let's check,

\bf \textit{middle point of 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -2}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ -8}}\quad ,&{{ -3}})
\end{array}\qquad 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{-8-2}{2}~,~\cfrac{-3+5}{2} \right)\implies (-5~,~1)

so, now we know the center coordinates and the radius, let's plug them in,

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}\\
&-5&1&5
\end{array}
\\\\\\\
[x-(-5)]^2-[y-1]^2=5^2\implies (x+5)^2-(y-1)^2=25

8 0
3 years ago
Select the correct answer. A triangle has vertices (-1, 2), (3, 1), and (7, 2). What is the approximate perimeter of th...
Eva8 [605]

Answer:

16.24 Units

Step-by-step explanation:

The perimeter of the triangle is the sum of the length of the sides of the triangle. Given the points on the vertices, the length of each side may be found using the formula

Length = √(x2 - x1)^2 + (y2 - y1)^2

Considering the pair (-1, 2), (3, 1), the length of that side

= √(3 -- 1)^2 + (1-2)^2)

= √(16 + 1)

= √17 units

Considering the pair (-1, 2), (7, 2), the length of that side

= √(7 -- 1)^2 + (2-2)^2)

= √(64)

= 8

Considering the pair  (3, 1),  and (7, 2), the length of that side

= √(7 - 3)^2 + (2  - 1)^2

= √(16 + 1)

= √17

Hence the perimeter of the triangle

= √17 + 8 + √17

= 4.12 + 8 + 4.12

= 16.24 Units

5 0
3 years ago
Geometry!!!!!!!!!!!!!!!!!!!!!!!!
Stella [2.4K]

<u>Given</u>:

Given that O is the center of the circle.

The radius of the circle is 3 m.

The measure of ∠AOB is 30°

We need to determine the length of the major arc ACB

<u>Measure of major ∠AOB:</u>

The measure of major angle AOB can be determined by subtracting 360° and 30°

Thus, we have;

Major \ \angle AOB=360-30

Major \ \angle AOB=330^{\circ}

Thus, the measure of major angle is 330°

<u>Length of the major arc ACB:</u>

The length of the major arc ACB can be determined using the formula,

<u></u>m \widehat{ACB}=(\frac{\theta}{360})2 \pi r<u></u>

Substituting r = 3 and \theta=330, we get;

m \widehat{ACB}=(\frac{330}{360})2 \pi (3)

m \widehat{ACB}=\frac{1980}{360}\pi

m \widehat{ACB}=5.5 \pi

Thus, the length of the major arc ACB is 5.5π m

8 0
3 years ago
How do you use ratio to compare mass
BartSMP [9]

Apply the law of multiple proportions to the two compounds. For each compound, find the grams of copper that combine with 1.00 g of chlorine by dividing the mass of copper by the mass of chlorine. Then find the ratio of the masses of copper in the two compounds by dividing the larger value by the smaller value.

hoping this helps

3 0
3 years ago
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