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Ghella [55]
3 years ago
7

What's the answer to this quadratic equation (x - 18)^2 = 1

Mathematics
2 answers:
just olya [345]3 years ago
5 0

Answer:

Its either x=17 or x=19

Step-by-step explanation:

Rus_ich [418]3 years ago
4 0

Answer:

x=17 or x=19

Step-by-step explanation:

(x−18)^2=1

First, simplify both sides of the equation.

x*2−36x+324=1

Then subtract 1 from both sides.

x^2−36x+324−1=1−1

x^2−36x+323=0

Factor left side of equation.

(x−17)(x−19)=0

Then set factors equal to 0.

x−17=0 or x−19=0

x=17 or x=19

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Which parent function is graphed below
aleksandrvk [35]

Answer:

the answer for this question is c because that is the answer

4 0
3 years ago
A trough of water is 20 meters in length and its ends are in the shape of an isosceles triangle whose width is 7 meters and heig
Vaselesa [24]

Answer:

a) Depth changing rate of change is 0.24m/min, When the water is 6 meters deep

b) The width of the top of the water is changing at a rate of 0.17m/min, When the water is 6 meters deep

Step-by-step explanation:

As we can see in the attachment part II, there are similar triangles, so we have the following relation between them \frac{3.5}{10} =\frac{a}{h}, then a=0.35h.

a) As we have that volume is V=\frac{1}{2} 2ahL=ahL, then V=(0.35h^{2})L, so we can derivate it \frac{dV}{dt}=2(0.35h)L\frac{dh}{dt} due to the chain rule, then we clean this expression for \frac{dh}{dt}=\frac{1}{0.7hL}\frac{dV}{dt} and compute with the knowns \frac{dh}{dt}=\frac{1}{0.7(6m)(20m)}2m^{3}/min=0.24m/min, is the depth changing rate of change when the water is 6 meters deep.

b) As the width of the top is 2a=0.7h, we can derivate it and obtain \frac{da}{dt}=0.7\frac{dh}{dt}  =0.7*0.24m/min=0.17m/min The width of the top of the water is changing, When the water is 6 meters deep at this rate

8 0
3 years ago
A 13-ounce box of cereal sells for $3.25. An 18-ounce box of cereal sells for $3.60. Which statement describes the difference in
ivolga24 [154]

Answer:

its c

Step-by-step explanation:

7 0
2 years ago
Which of the following linear relationships is NOT also a proportional relationship?
katen-ka-za [31]

The linear relationships that are proportional relationship are y = (-2)x , y = (3/5)x  , y = - (1/2)x  .

A linear relationship in the form of y = mx + c is said to be a proportional relationship when c = 0  .

in the question

Part(a)

the equation is  y = (2)x - 3

on comparing it with y = mx + c , we get c = -3 , which is not 0 .

So , it is not a proportional relationship .

Part(b)

the equation is  y = (-2)x

on comparing it with y = mx + c , we get c = 0 ,

So , it is a proportional relationship .

Part(c)

the equation is  y = (3/5)x

on comparing it with y = mx + c , we get c = 0 ,

So , it is a proportional relationship .

Part(d)

the equation is  y = - (1/2)x

on comparing it with y = mx + c , we get c = 0 ,

So , it is a proportional relationship .

Therefore, The linear relationships that are proportional relationship are y = (-2)x , y = (3/5)x  , y = - (1/2)x  , that are options (b) , (c) and (d) .

The given question is incomplete , the complete question is

Which of the following linear relationships is NOT also a proportional relationship?

(a) y = (2)x - 3

(b) y = (-2)x

(c) y = (3/5)x

(d) y = - (1/2)x

Learn more about Proportionality here

brainly.com/question/14967814

#SPJ1

8 0
1 year ago
A car covered a certain distance at a speed of 24 mph. While returning, the car covered the same distance at a speed of 16 mph.
Ymorist [56]

Answer:

19.2 mph

Step-by-step explanation:

just trust me

7 0
3 years ago
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