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natita [175]
3 years ago
9

What is the approximate measure of I

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
3 0
Let θ = m∡I

tan θ = 20/21
tan⁻¹ (20/21) = θ

θ ≈ 43.60° or if you need to round to another decimal point, plug the equation I put in bold into a calculator. 
Black_prince [1.1K]3 years ago
3 0
Tan I = opposite/adjacent
        = segment TR/segment TI
         = 20/21
tan^-1(tan I) = tan^-1 (20/21)
                  I = 43.6°  
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Answer:

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Step-by-step explanation:

Remark

This is just the reverse of the question you just did. This time you are trying to solve for c

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Solution

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c^2 = 8^2 + 11^2       Expand

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c =  13.601                   Round to the nearest 1/100 th

c = 13.60                      Note: the zero must be there or the answer does not show the nearest 1/100 th

8 0
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