Answer:
MQ = 16.4
By the <u>Parallelogram Diagonals Theorem</u> , MP = <u>PQ</u>
So MQ = 2 · <u>MP</u>
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Step-by-step explanation:
<u>Parallelogram Diagonals Theorem</u>
The diagonals of a parallelogram bisect each other, i.e. they divide each other into <em>two equal parts</em>.
P is the point of intersection of the diagonals.
Therefore, MP = PQ and LP = PN
If MP = 8.2, then PQ = 8.2
⇒ MQ = 8.2 + 8.2 = 16.4
Answer:
a) (i)
, (ii)
, (iii)
, (iv)
, (v)
, (vi)
, (vii)
, (viii)
; b)
; c) The equation of the tangent line to curve at P (7, -2) is
.
Step-by-step explanation:
a) The slope of the secant line PQ is represented by the following definition of slope:

(i)
:




(ii) 




(iii) 




(iv) 




(v) 




(vi) 




(vii) 




(viii) 




b) The slope at P (7,-2) can be estimated by using the following average:



The slope of the tangent line to the curve at P(7, -2) is 2.
c) The equation of the tangent line is a first-order polynomial with the following characteristics:

Where:
- Independent variable.
- Depedent variable.
- Slope.
- x-Intercept.
The slope was found in point (b) (m = 2). Besides, the point of tangency (7,-2) is known and value of x-Intercept can be obtained after clearing the respective variable:



The equation of the tangent line to curve at P (7, -2) is
.
Answer:
The line would be y = 2x + 5
Step-by-step explanation:
To find a parallel line, we first need to note that the slope of the original line is 2. This means the slope of our new line will also be 2 because parallel lines have the same slope.
So we use the slope we found along with the point given in point-slope form. Then we solve for y.
y - y1 = m(x - x1)
y - 11 = 2(x - 3)
y - 11 = 2x - 6
y = 2x + 5
One dozen eggs is 48 eggs. Altogether that costs 40 dollars. If six of the eggs were broken then the money wasted would be 5 dollars.
The reason that it is 5 dollars is becuase it takes 10 to buy 12 eggs, and half of that is 6. So divide both 12 and 10 (separately) and you get 5 dollars for 6 eggs.
To get the percent you must divide 5 by 40.
The answer comes out to about 12.5% or 0.125.
So in the end, 12.5% of the money was wasted due to the broken eggs.
Hope this helped!