Answer:
d=~7.6
Step-by-step explanation:
7^2+3^2=d^2
49+9=d^2
58=d^2
Square root of 58=~7.6
d=~7.6
Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
There are two solutions.
.. (3, 2)
.. (0.2, -3.6)
_____
If you're choosing possibilities from a list, trying them in the equations usually gives quick results.
Answer:
x= -4
Step-by-step explanation:
The answer is 6m - 6 = 8m + 4
Hope this helps please give brainless!!!
