Question

hi can i please have some help w/ these! i have my exam tomorrow!!! factoring algebra 2! worth 35 points!

Answer 1

Answer:

11. $4x^{3}-10x^{2}+6x$

Take out 2x ( greatest common factor )
$2x(2x^{2}-5x+3)$

Factor

$2x(2x^{2} -2x-3x+3)$

$2x(x-1)-3(x-1)=(2x-3)(x-1)$

Don't forget about the 2x we took out earlier

Solution to 11: $2x(2x-3)(x-1)$

12. $16x^{2} -25y^{2}$

This is the difference of squares, so let's use the formula...

$a^{2}-b^{2}=(a-b)(a+b)$

if, $a=16x^{2}$ and $b=25y^{2}$

then, the Solution to 12 is:

$(4x-5y)(4x+5y)$

13. $3x^3-24$

First of all, you must find the greatest common factor because there isn't anything else you can do.

$3(x^3-8)$

Now you can see the difference of cubes...

$a^3-b^3=(a-b)(a^2+ab+b^2)$

so, the Solution to 13 is:

$3(x^3-8)= 3(x-2)(x^2+2x+4)$