Answer:
a. See attachments
B. 163630.2ft
C. 147056.70ft
D. 49205.4ft
Step-by-step explanation:
Check attachments for details
Angle a.. Angle of dep to beginning of runway
Angle b... Angle of del to end of runway
AD... Altitude of plane
DB..... Ground distance before touch down
AC... Air distance travelled until touch down on the near end of runway
A- solve bracket first so
3/4 + 2/9 +5/12 then multiply by 3.6 = 5
do the same with the rest and u get
A=5
B=1
C=15
D=3
please mark brainliest
<span>Well first this one you can just count which ones are 9 units away so it could be A becuase -4+-9=-13
Another is B because
-4+9=5
</span>I hope it helps.
Comment if you need more help
Answer:
7.5 MW
Step-by-step explanation:
The power generated from a falling water is a function of its height and volume. The power generated an be calculated using the formula:
Power (P) = Density(ρ) * volume flow rate(Q) * acceleration due to gravity(g) * height(h)
P = ρQgh
But Qh = Velocity(v) * volume(V).
Hence power = ρvgV
Given that ρ of water = 1000 kg/m³, v = 75 m/s, V = 10 m³, g = 10 m/s². Substituting:
P = ρvgV = 1000 * 75 * 10 * 10 = 7500000 W
P = 7.5 MW
Answer:
1,2,1
Step-by-step explanation:
