Answer:
it is 60
Step-by-step explanation:
you add all the numbers than you round it, the number is 0 so it stays the same, hope it helps, murdle
Answer:
3. x = 17
4. a. m<NMP = 48°
b. m<NMP = 60°
Step-by-step explanation:
3. Given that <BAM = right angle, and
m<BAM = 4x + 22, set 90° equal to 4x + 22 to find x.
4x + 22 = 90
Subtract 22 from both sides
4x + 22 - 22 = 90 - 22
4x = 68
Divide both sides by 4
4x/4 = 68/4
x = 17
4. a. m<NMQ = right angle (given)
m<PMQ = 42° (given)
m<PMQ + m<NMP = m<NMQ (angle addition postulate)
42 + m<NMP = 90 (substitution)
m<NMP = 90 - 42 (subtracting 42 from each side)
m<NMP = 48°
b. m<NMQ = right angle (given)
m<NMP = 2*m<PMQ
Let m<PMQ = x
m<NMP = 2*x = 2x
2x + x = 90° (Angle addition postulate)
3x = 90
x = 30 (dividing both sides by 3)
m<PMQ = x = 30°
m<NMP = 2*m<PMQ = 2*30
m<NMP = 60°
24/6=4 24/8=3 4/4=1 12/6=2 48/8=6 give me a thanks and message me all the other ones u want me to answer
The child's starting and finishing location is the same, therefore the displacementnis zero.
I don't know what the "six-step method" is supposed to be, so I'll just demonstrate the typical method for this problem.
Let <em>x</em> be the amount (in gal) of the 50% antifreeze solution that is required. The new solution will then have a total volume of (<em>x</em> + 60) gal.
Each gal of the 50% solution used contributes 0.5 gal of antifreeze. Similarly, each gal of the 30% solution contributes 0.3 gal of antifreeze. So the new solution will contain (0.5 <em>x</em> + 0.3 * 60) gal = (0.5 <em>x</em> + 18) gal of antifreeze.
We want the concentration of antifreeze to be 40% in the new solution, so we need to have
(0.5 <em>x</em> + 18) / (<em>x</em> + 60) = 0.4
Solve for <em>x</em> :
0.5 <em>x</em> + 18 = 0.4 (<em>x</em> + 60)
0.5 <em>x</em> + 18 = 0.4 <em>x</em> + 24
0.5 <em>x</em> - 0.4 <em>x</em> = 24 - 18
0.1 <em>x</em> = 6
<em>x</em> = 6/0.1 = 60 gal
