Answer:
D. 9
Step-by-step explanation:
Let
abc=100a+10b+c
bca=100b+10c+a
cab=100c+10a+b
abc + bca + cab=(100a+10b+c) + (100b+10c+a) + (100c+10a+b)
=100a + 10b + c + 100b + 10c + a + 100c + 10a + b
Collect like terms
=100a + a + 10a + 10b + 100b + b + c + 10c + 100c
=111a + 111b + 111 c
Factorise
=111(a+b+c)
abc + bca + cab = 111(a+b+c)
Factors of 111(a+b+c)= 1, 3, 37, 111, and (a+b+c)
abc + bca + cab is divisible by a+b+c because it is a factor of 111(a+b+c)
abc + bca + cab is divisible by 3 because 3 is a factor of 111(a+b+c)
abc + bca + cab is divisible by 37 because 37 is a factor of 111(a+b+c)
abc + bca + cab is not divisible by 9 because 9 is not a factor of 111(a+b+c)
Hi there
To answer you question the answer is:
Carrie read at a rate of 27.5 pages per hour.
Answer:
Hala would have 10 candies, Ahmed would have 35, and Eman would have 45.
Step-by-step explanation:
if the candy is given out 2:7:9, add the numbers and devide. 90 ÷ 18 is five so multiply each number by 5 to get 10:35:45
D) because the final answer should be 8/3. See the attachment.
A. (-3,0) thats the answer i have
