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Orlov [11]
3 years ago
12

Help this is due today

Mathematics
2 answers:
PolarNik [594]3 years ago
8 0
C=-4

14= -2c -6 -3c
Add 6 to both sides and combine like terms:
20=-5c
Divide both by -5:
-4=c
C=-4
Elodia [21]3 years ago
3 0

Answer:

-1.4 i think

Step-by-step explanation:

14-6 is 7

combine -2c and -3c to get -5c

7=-5c

7/-5 =

-1.4

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On a piece of paper, graph f(x) 2x>3
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3 years ago
The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,
professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0
3 years ago
Branliest to correct answer no guessing please
Ann [662]

Answer:

THE CORRECT IS B(a and b)= p(A).P(B)

3 0
3 years ago
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