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Lisa [10]
2 years ago
10

What is the surface area of a 24ft by 16 ft cylinder 288ft2 , 384ft2 , 19ft2 , 672ft2

Mathematics
1 answer:
Viefleur [7K]2 years ago
4 0

The surface area of the cylinder will be 1206.37 square feet.

<h3>What is surface area?</h3>

The space occupied by any two-dimensional figure in a plane is called the area. The area of the outer surface of any body is called as the surface area.

Given that the radius of the cylinder is r = 12 ft and the length of the cylinder is 16 ft.

The volume of the cylinder is calculated as:-

V = 2πrl

V = 2 x π x 12 x 16

V = 1206.37 square feet.

Therefore the surface area of the cylinder will be 1206.37 square feet.

To know more about a surface area follow

brainly.com/question/25292087

#SPJ1

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Using a Table to Multiply Multivariable Polynomials What is the product of 6x – y and 2x – y + 2? 8x2 – 4xy + 12x + y2 – 2y 12x2
NikAS [45]

Answer: B.

12x^{2} -8xy + 12x + y^2 - 2y

Step-by-step explanation:

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3 years ago
Mark rolls 2 fair dice and adds the results from each. Work out the probability of getting a total of 5. Please help if you can!
Allisa [31]

Answer:

13.8%

Step-by-step explanation:

I have created a table that shows all of the possibilities that two die's can roll when summed up. If we count all of these possibilities we can see that there are a total of 36 outcomes. From all of these outcomes we can also see that only 4 outcomes sum up to be a total of 5. Therefore, we have to divide the number of times 5 is a possibility by the total number of outcomes to get the probability of actually getting a sum of 5.

5 / 36 = 0.138  ... multiply by 100 to get percentage

0.138 * 100 = 13.8%

3 0
3 years ago
A group of 10 fisherman enjoy certain types of fish, 3 of them like salmon, 5 like trout and 2 like bass. A single fisherman is
Gelneren [198K]
There are a total of 10 fishermen as stated in the given. The probability that a chosen fisherman liked salmon is 3/10. Also, the probability that a fisherman liked bass is 2/10. By using the conjunction "or" we add the probabilities of these events to arrive with the answer giving us 5/10 or 1/2. The answer is letter D. 
5 0
3 years ago
In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any
Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

E \cap F = \emptyset,\quad E \cup F = \Omega

where \Omega is the whole sample space.

This implies that

P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day d_1.

The second footballer can be born on any other day, so he has 364 possible birthdays:

d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}

the probability for the first two footballers to be born on two different days is thus

1 \cdot \dfrac{364}{365} = \dfrac{364}{365}

Similarly, the third footballer can be born on any day, except d_1 and d_2:

d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}

so, the probability for the first three footballers to be born on three different days is

1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

So, the probability that at least two footballers are born on the same day is

1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

since the two events are complementary.

8 0
3 years ago
Select four statements from the invertible matrix theorem and show that all four statements are true or false
Lelechka [254]

Answer:

A) A is an invertible matrix ( TRUE )

B) A is a row equivalent to the n x n identity matrix ( n = 3 ) ( TRUE )

C ) The equation Ax = 0 has only the trivial solution ( TRUE )

D ) The columns of A form a linearly independent set ( TRUE )

Step-by-step explanation:

Assuming a matrix A

\left[\begin{array}{ccc}1&2&1\\-1&0&3\\4&1&5\end{array}\right]

det A = 1 [ 0 -3 ] +  2 [12 + 5 ]  + 1[-1]

        = -3 + 34 -1 = 30 ≠ 0

THEREFORE  det A = 30 ≠ 0

Attached is the detailed solution of the given statements above

5 0
3 years ago
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