Answer:
3x+4x+y-2+1+2
Step-by-step explanation:
Answer:
The Solution set is (x,y){(2,5)}
Step-by-step explanation:
The given equation is:
6x+4y=32
-6x+4y=8
We will use the elimination method:
By this method we will eliminate the variable x.
6x+4y=32
-6x+4y=8
________
8y=40
Divide both the sides by 8
8y/8=40/8
y=5
Now substitute the value of y in equation 2:
-6x+4y=8
-6x+4(5)=8
-6x+20=8
Move the constant value to the R.H.S
-6x=8-20
-6x= -12
Divide both the terms by -6
-6x/-6 = -12/-6
x= 2
The Solution set is (x,y){(2,5)}....
V=29,564-532t would be the equation for that scenario
I'll do problem 13 to get you started.
The expression
is the same as 
Then we can do a bit of algebra like so to change that n into n-1

This is so we can get the expression in a(r)^(n-1) form
- a = 8/7 is the first term of the geometric sequence
- r = 2/7 is the common ratio
Note that -1 < 2/7 < 1, which satisfies the condition that -1 < r < 1. This means the infinite sum converges to some single finite value (rather than diverge to positive or negative infinity).
We'll plug those a and r values into the infinite geometric sum formula below
S = a/(1-r)
S = (8/7)/(1 - 2/7)
S = (8/7)/(5/7)
S = (8/7)*(7/5)
S = 8/5
S = 1.6
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Answer in fraction form = 8/5
Answer in decimal form = 1.6