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Naily [24]
3 years ago
6

Straight line depreciation. A car has an initial value of 29,564 and depreciates 532 a year . V represents value of car after t

years. Write a symbolic rule that expresses V in terms of t
Mathematics
1 answer:
LenaWriter [7]3 years ago
5 0
V=29,564-532t would be the equation for that scenario
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The sum of four and three multiplied by the quotient of four and two
asambeis [7]

Answer:

14

Step-by-step explanation:

4+3=7

4/2=2

7•2=14

8 0
3 years ago
2 more ASAP thanks for all the help btw
natta225 [31]

Answer: B

Step-by-step explanation:

It's the only one that's correct.

3 0
3 years ago
Read 2 more answers
(look at image) can i get help with this?
navik [9.2K]

Answer:

m∡A = 14

m∡B = 76

Step-by-step explanation:

Two Angles are Complementary when they add up to 90 degrees.

So 3x -7 + 11x - 1 = 90, which we can solve.

14x - 8 = 90

14x = 98

x = 98/14 = 7

with the knowledge of x=7, we can find the angles:

m∡A = 3·7 - 7 = 14

m∡B = 11·7 - 1 = 76

Supplementary angles are angles that add up to 180 degrees, so the next assignment is very comparable, try it!

4 0
3 years ago
Solve for side BC pls help
defon

Step-by-step explanation:

hope this helps you with the question

6 0
3 years ago
A random sample of 20 recent weddings in a country yielded a mean wedding cost of $ 26,388.67. Assume that recent wedding costs
Makovka662 [10]

Answer:

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) For the interpretation of the result, option D is correct.

We can be​ 95% confident that the mean​ cost, μ​, of all recent weddings in this country is somewhere within the confidence interval.

c) Option B is correct.

The population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Step-by-step explanation:

Sample size = 20

Sample Mean = $26,388.67

Sample Standard deviation = $8200

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 26,388.67

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 20 - 1 = 19.

Significance level for 95% confidence interval

(100% - 95%)/2 = 2.5% = 0.025

t (0.025, 19) = 2.086 (from the t-tables)

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 8200

n = sample size = 20

σₓ = (8200/√20) = 1833.6

99% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 26,388.67 ± (2.093 × 1833.6)

CI = 26,388.67 ± 3,837.7248

99% CI = (22,550.9452, 30,226.3948)

99% Confidence interval = (22,550.95, 30,226.40)

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) The interpretation of the confidence interval obtained, just as explained above is that we can be​ 95% confident that the mean​ cost, μ​,of all recent weddings in this country is somewhere within the confidence interval

c) A further explanation would be that the population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Hope this Helps!!!

4 0
3 years ago
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