All categories

2 years ago

Point T is on line segment S U ‾ SU . Given S T = 6 ST=6 and T U = 10 , TU=10, determine the length S U ‾ . SU

Mathematics

1 answer:

Naily [24]2 years ago

5 0

If Point T is on the line segment S U, then ST + TU = SU, Hence the length of SU is 16.

<h3>What is addition?</h3>

The addition is one of the mathematical operations. The addition of two numbers results in the total amount of the combined value.

If Point T is on the line segment S U, then ST + TU = SU

Given;

S T = 6 and T U = 10

Substitute

SU = ST + TU

SU = 6 + 10

SU = 16

Hence the length of SU is 16.

Learn more about lines;

brainly.com/question/24077229

#SPJ1

You might be interested in

PLEASE HELP!!!! a bag holds 25 potatoes, if the potatoes in the bag are split among 5 people, how many people does each person g

Airida [17]

Answer:

25 potatoes split between 5 people would be 25÷5=5. So each person will get 5 potatoes.

6 0

3 years ago

Read 2 more answers

Write in standard form 4,000,000+3,000+50+2

Andreas93 [3]

4,003,052 is the answer to the problem

7 0

3 years ago

Read 2 more answers

What is the result when x^3-2x^2+5x-13x 3 −2x 2 +5x−13 is divided by x-2x−2?

Aleksandr [31]

yo k se wey: rg`weaofjwafgEWF3WRF1QTFG3Q2TGF2

3 0

3 years ago

A+b+c=31 2a+3b+4c=105 who's a,b,c

Alik [6]

Answer:

begin{aligned}

& x = \frac{D_x}{D} = \frac{-616}{-154} = 4 \\

& y = \frac{D_y}{D} = \frac{ 616}{-154} = -4 \\

& z = \frac{D_z}{D} = \frac{-770}{-154} = 5

\end{aligned} $begin{aligned} & x = \frac{D_x}{D} = \frac{-616}{-154} = 4 \\ & y = \frac{D_y}{D} = \frac{ 616}{-154} = -4 \\ & z = \frac{D_z}{D} = \frac{-770}{-154} = 5 \end{aligned}$

Step-by-step explanation:

4 0

4 years ago

Need help in understanding how to solve this problem.

Feliz [49]

Answer:

Step-by-step explanation:

3x+y+z= 4

3x+ y = 4 - z

y = 4-z-3x

We then make parallel

y-2 = 4−z−3x

y-2 = 4-2 -z-3x

y-2 = 2-z-3x

y = -z-3x+2

7 0

3 years ago