Answer:
C
Step-by-step explanation:
If you have a Ti-84 series calculator, press "stat" then "Edit..." and then fill in the data table values for x and y in two lists. Then press "2nd" and "mode" to quit. Now press "stat" again and right arrow over to "calc" and press down until you find "ExpReg" and set the "Xlist" and "Ylist" that you used and you will get C as the answer. Another way to do this is to manually substitute values into all 4 equations, which is boring.
Answer: $27.5
Step-by-step explanation:
From the question, we are informed that employee works 40 hours and earns $1,100, to calculate the amount that the employee earn per hour will be:
Amount earned = $1100
Number of hours worked = 40 hours
Amount earned per hour = $1100/40 = $27.5
41 hours or more
to make $600 she will need to work 40 hours, but she wants to make more than $600 so she needs to work more than 40 hours.. 600/15=40
i hope this helps
9514 1404 393
Answer:
a) x = {-1, 3, 4}
b) (0.472, 13.128)
c) (3.528, -1.128)
d) x < 0.472 U x > 3.528
e) 0.472 < x < 3.528
Step-by-step explanation:
This is a cubic (odd degree) function with a positive leading coefficient, so it will be increasing until the first turning point, and after the last turning point. It will be decreasing between the turning points.
a) A graph shows the zeros to be x = -1, x = 3, x = 4.
b) A graph shows the local maximum to be approximately (0.472, 13.128). The x-coordinate of this point is exactly 2-√(7/3).
c) The local minimum is about (3.528, -1.128). Its x-coordinate is exactly 2+√(7/3).
d) As stated above, the increasing intervals are (-∞, 0.428) ∪ (3.528, ∞).
e) The decreasing interval is (0.428, 3.528).
_____
<em>Additional comments</em>
The sum of odd-degree term coefficients is the same as the sum of coefficients of even-degree terms, so you know one of the roots is -1. Factoring that out gives the quadratic x^2 -7x +12 = (x -3)(x -4), so the other two roots are 3 and 4.
The derivative is 3x^2 -12x +5 = 3(x -2)^2 -7, so its roots (turning points of f(x)) are 2±√(7/3).
I find a graphing calculator can show me the roots and turning points easily.