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Elena L [17]
2 years ago
5

a line has the equation 8x-2y=24 in standard form.Rewrite the equation of the line in slope intercept form.Then report the slope

and y intercept.
Mathematics
1 answer:
inna [77]2 years ago
6 0
8x-2y=24
-8x     -8x
-2y=-8x+24
----- ---- ----
  -2   -2   -2
y=4x-12

slope: 4
y-intercept: -12

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A rectangle has a length of 2x+7 and a width of 3x+8.
Phantasy [73]

Answer:

Below.

Step-by-step explanation:

Perimeter = 2(2x + 7 + 3x + 8)

= 2(5x + 15)

= 10x + 30.

3 0
2 years ago
Evaluate the expression below when x=-1. 2x^2-5/x+9
Greeley [361]

Hey there!


2x^2 - 5 / x + 9

= 2(-1)^2 - 5/ -1 + 9
= (2(-1)^2 - 5) / (-1 + 9)

= (2(1) - 5) / 8

= (2 - 5) / 8

= -3 / 8

≈ -0.375


Therefore, your answer is:

-3/8 OR -0.375

EITHER OF THOSE SHOULD WORK BECAUSE THEY ARE EQUIVALENT TO EACH OTHER!

Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

3 0
1 year ago
Pq lies on plane PQR. Point S lies on plane PQR. qs does not lie on plane PQR. Which two statements contradict each other?
Vinil7 [7]

Answer c: 2 and 3


Of course Q is on plane PQR. If S is as well, then QS is as well.



8 0
3 years ago
Mr. Jones bought a cloth of length 3890 cm. How much is the length in m and cm?
devlian [24]

Answer:

38m and 90cm

1m = 100cm

3890cm = 38m and 90cm

Step-by-step explanation:

1m = 100cm

3890cm = 38m and 90cm

3 0
2 years ago
Read 2 more answers
Consider the polynomial p(x) = x^3 + 4x^2 + 6x − 36.
Nady [450]

Answer:

a. attached graph; zero real: 2

b. p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)

c. the solutions are 2, -3-3i and -3+3i

Step-by-step explanation:

p(x) = x³ + 4x² + 6x - 36

a. Through the graph, we can see that 2 is a real zero of the polynomial p. We can also use the Rational Roots Test.

p(2) = 2³ + 4.2² + 6.2 - 36 = 8 + 16 + 12 - 36 = 0

b. Now, we can use Briott-Ruffini to find the other roots and write p as a product of linear factors.

2 |  1     4     6    -36

     1      6    18     0

x² + 6x + 18 = 0

Δ = 6² - 4.1.18 = 36 - 72 = -36 = 36i²

√Δ = 6i

x = -6±6i/2 = 2(-3±3i)/2

x' = -3-3i

x" = -3+3i

p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)

c. the solutions are 2, -3-3i and -3+3i

4 0
2 years ago
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