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1 year ago

If x is increased by 25% then, by what % is x² increased

1 answer:

5 0

By analytical methods and algebraic handling and on the basis that x is increased by 25 %, we conclude that the variable x² is increased by 18.75 %.

<h3>How to determine the percentage increase rate </h3>

In this case we have a linear variable x, whose increase is described by the following expression:

y = x · (1 + r/100) (1)

Where r is the increase rate.

If we square (1), then we find that:

y² = x² · (1 + r/100)² = (1 + r'/100) (2)

Where r' is the equivalent increase rate.

(1 + r/50 + r²/10000) = (1 + r'/100)

r'/100 = r/50 + r²/10000

r' = r/2 + r²/100

If we know that r = 25, then the equivalent increase rate is:

r' = 25/2 + 25²/100

r' = 18.75

By analytical methods and algebraic handling and on the basis that x is increased by 25 %, we conclude that the variable x² is increased by 18.75 %.

To learn more on percentages: brainly.com/question/14979505

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en un colegio mixto hay x estudiantes distribuidos en c cursos. Si hay m niños por curso, ¿Cuantas niñas hay en el colegio?

Tomtit [17]

La ecuación que nos dice cuantas niñas hay en el colegio es:

A = x - c*m

¿Como encontrar una expresión para la cantidad de niñas?

Sabemos que hay un total de x estudiantes, definimos las variables:

A = cantidad total de niñas
B = cantidad total de niños.

Entonces tenemos A + B = x

Tambien sabemos que los estudiantes estan divididos en c cursos, de tal forma que hay m niños por curso.

Entonces c por m es igual a la cantidad total de niños:

c*m = B

Reemplazando esto en la ecuación de arriba podemos obtener:

A + c*m = x

A = x - c*m

Esta es la ecuación que nos da el numero total de niñas en el colegio.

Sí quieres aprender más sobre ecuaciones, puedes leer:

brainly.com/question/18168483

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2 years ago

Help me with example 2 and 3

PolarNik [594]

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3 years ago

Which steps show how to use the distributive property to evaluate 9.32?

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2 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!!!! Can U Answer All These.

mash [69]

QUESTION 1

In figure A, the area of the bigger square is $625\:units^2$ . This means that the length of this square is the hypotenuse of the right angle triangle formed, which is $25\:units$ .

The area of the two smaller squares are $576\:units^2$ and $49\:units^2$ .

The length of these two squares form the two shorter legs of the right angle triangle, which are $24$ and $7$ units respectively.

Therefore we can write the equation, $576+49=625$ .

This implies that, $24^2+7^2=25^2$

We can see that the sum of the squares of the two shorter legs equals the square of the longer side which is the hypotenuse and this what the Pythagoras theorem says.

But in fig. B,

$5^2+4^2\ne 6^2$