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Zanzabum
3 years ago
10

Michael’s class 27 adults and 63 kids on their field trip. Emily’s class had 20 adults and 70 kids on their trip. Both Michael &

amp; Emily’s teachers split the class into groups, so that each group has 7 kids. Whose class had more adult chaperones per group?
Mathematics
2 answers:
algol [13]3 years ago
6 0

Answer:

Michaels class

Step-by-step explanation:

63 kids and 70 kids One group gets 9 groups and the other gets 10. 27/9 is 3, whileas 20/10 is 2 so Michaels class had more. Hope this helps :D

Lelu [443]3 years ago
5 0

Answer:

Emily's class

Step-by-step explanation:

Emily's class had more students than Michael's class. This shows numerically and technically that Emily's class needed more chaperones per each 7 students.

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Of all 25 marbles in a bag, 3 of the marbles
Tom [10]

Answer:

You have a 12% chance of pulling out a white marble

Step-by-step explanation:

Their is 25 marbles in the bag and you have 3 out of 25 chance of pulling out a white marble. 3/25=0.12 so you have a 12% chance of pulling out a white marble.

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3 years ago
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Perimeter and Circumference! Only 5 questions
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Answer:

1) 17.5

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Step-by-step explanation:

ohhhh yes

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3 years ago
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A water tank is in the shape of a right rectangular prism. Its dimensions are 6 feet by 4 feet by 7 feet. What is the surface ar
Norma-Jean [14]

Answer:

\LARGE{ \underline{\underline{ \sf{\pink{ Required\: answer:}}}}}

<h2><u>GIVEN</u><u> </u>- </h2>

  • Water tank which is in a shape of right rectangular prism

Dimensions = 6 feet × 4 feet × 7 feet

<h3><u>TO</u><u> </u><u>FIND</u><u> </u><u>-</u><u> </u> </h3>

  • Surface area of tank

<h2><u>SOLUTION</u> - </h2>

<em><u>Using</u></em><em><u> </u></em><em><u>formula</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>surface</u></em><em><u> </u></em><em><u>area</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>right</u></em><em><u> </u></em><em><u>rectangular</u></em><em><u> </u></em><em><u>prism</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em>

Surface area =

2(wl  + hl + hw)

L = length

w = width

h = height

( assumimg 6 feet = L , 4 feet = W , 7 feet = h)

Putting value of L, W and H in the equation. we get,

=2(4 × 6 + 7 × 6 + 7× 4)

= 2(24 + 42 + 28)

= 2( 94)

= 2 × 94

= 188

7 0
3 years ago
Read 2 more answers
The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacemen
mamaluj [8]
<h2>Answer:</h2>

(a)

The probability is :  1/2

(b)

The probability is :  1/2

<h2>Step-by-step explanation:</h2>

The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2)   (1,3)    (1,4)    (1,5)

(2,1)   (2,3)   (2,4)   (2,5)

(3,1)   (3,2)   (3,4)   (3,5)

(4,1)   (4,2)   (4,3)   (4,5)

(5,1)   (5,2)   (5,3)   (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

We know that it could be calculated by using the formula:

P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is:  (4,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( since, the only outcome out of 20 outcomes is:  (3,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

7 0
3 years ago
What is the y coordinate of the point that divides the
svet-max [94.6K]

Answer:

the y coordinate is 5

Step-by-step explanation:

In the figure attached, the  directed line segment is shown.

J is located at (-3, 1) and K is located at (-8, 11)

run: x2 -x1 = -8 - (-3) = -5

rise: y2 - y1 = 11 - 1 = 10

Taking J as reference, the coordinate of the point that divides the  directed line segment from J to k into a ratio of 2:3 is:

c = 2/(2+3) = 0.4

(x1 + c*run, y1 + c*rise)

(-3 + 0.4*-5, 1+0.4*10)

(-5, 5)

6 0
3 years ago
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