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shutvik [7]
2 years ago
14

Which number line represents the solution set for the inequality 3(8 – 4x) < 6(x – 5)?

Mathematics
1 answer:
Nady [450]2 years ago
3 0

Answer:

x>3

Step-by-step explanation:

Which number line represents the solution set for the inequality 3(8 – 4x) < 6(x – 5)?

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Thepotemich [5.8K]

The domain of the functions are:

  • The domain of f(x) = √4x + 6 is [-3/2, ∞) or x >-3/2
  • The domain of g(x) = -4√-20x - 6 is (-∞, -3/10] or x < -3/10
  • The domain of f(x) = 15 + √5x - 16 is [16/5, ∞) or x >16/5
  • The domain of p(x) = √20x + 6 is (-3/10, ∞] or x > -3/10

<h3>What are the domains of a function?</h3>

The domain of a function is the set of input values the function can take i.e. the set of values the independent variable can assume?

<h3>How to determine the domain of the functions?</h3>

<u>Function 1</u>

The function is given as:

f(x) = √4x + 6

Set the radicand greater than 0

4x + 6 > 0

Subtract 6 from both sides

4x > -6

Divide by 4

x > -3/2

Express as interval notation

[-3/2, ∞)

Hence, the domain of f(x) = √4x + 6 is [-3/2, ∞) or x >-3/2

<u>Function 2</u>

The function is given as:

g(x) = -4√-20x - 6

Set the radicand greater than 0

-20x - 6 > 0

Add 6 to both sides

-20x > 6

Divide by -20

x < -6/20

Simplify

x < -3/10

Express as interval notation

(-∞, -3/10]

Hence, the domain of g(x) = -4√-20x - 6 is (-∞, -3/10] or x < -3/10

<u>Function 3</u>

The function is given as:

f(x) = 15 + √5x - 16

Set the radicand greater than 0

5x - 16 > 0

Add 16 to both sides

5x > 16

Divide by 5

x > 16/5

Express as interval notation

[16/5, ∞)

Hence, the domain of f(x) = 15 + √5x - 16 is [16/5, ∞) or x >16/5

<u>Function 4</u>

The function is given as:

p(x) = √20x + 6

Set the radicand greater than 0

20x + 6 > 0

Subtract 6 from both sides

20x > -6

Divide by 20

x > -6/20

Simplify

x > -3/10

Express as interval notation

(-3/10, ∞]

Hence, the domain of p(x) = √20x + 6 is (-3/10, ∞] or x > -3/10

Read more about domain at:

brainly.com/question/10197594

#SPJ1

3 0
2 years ago
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