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Harrizon [31]
3 years ago
15

under the tree ba dum ba dum under the tree ba dum ba dum i am a dog under the log under the tree ba dum ba dum

Mathematics
2 answers:
Sidana [21]3 years ago
7 0

Answer:

.______________.

Step-by-step explanation:

AleksAgata [21]3 years ago
6 0

Answer:

Under the sea bam ba bam  Under the sea bam ba bam  I am a crab and im under the sea

Step-by-step explanation:

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Lai Yee and Khadijah have 60 stamps. When Lai Yee gives 5 stamps to Khadijah, the number of Lai Yee's stamps is twice the number
Radda [10]

Answer:

Lai yee : 45

Khadijah : 15

Step-by-step explanation:

Here is the Explanation

8 0
2 years ago
How many different combinations are possible if each lock contains the numbers 0 to 39, and each combination contains three dist
Georgia [21]
(e) Each license has the formABcxyz;whereC6=A; Bandx; y; zare pair-wise distinct. There are 26-2=24 possibilities forcand 10;9 and 8 possibilitiesfor each digitx; yandz;respectively, so that there are 241098 dierentlicense plates satisfying the condition of the question.3:A combination lock requires three selections of numbers, each from 1 through39:Suppose that lock is constructed in such a way that no number can be usedtwice in a row, but the same number may occur both rst and third. How manydierent combinations are possible?Solution.We can choose a combination of the formabcwherea; b; carepair-wise distinct and we get 393837 = 54834 combinations or we can choosea combination of typeabawherea6=b:There are 3938 = 1482 combinations.As two types give two disjoint sets of combinations, by addition principle, thenumber of combinations is 54834 + 1482 = 56316:4:(a) How many integers from 1 to 100;000 contain the digit 6 exactly once?(b) How many integers from 1 to 100;000 contain the digit 6 at least once?(a) How many integers from 1 to 100;000 contain two or more occurrencesof the digit 6?Solutions.(a) We identify the integers from 1 through to 100;000 by astring of length 5:(100,000 is the only string of length 6 but it does not contain6:) Also not that the rst digit could be zero but all of the digit cannot be zeroat the same time. As 6 appear exactly once, one of the following cases hold:a= 6 andb; c; d; e6= 6 and so there are 194possibilities.b= 6 anda; c; d; e6= 6;there are 194possibilities. And so on.There are 5 such possibilities and hence there are 594= 32805 such integers.(b) LetU=f1;2;;100;000g:LetAUbe the integers that DO NOTcontain 6:Every number inShas the formabcdeor 100000;where each digitcan take any value in the setf0;1;2;3;4;5;7;8;9gbut all of the digits cannot bezero since 00000 is not allowed. SojAj= 9<span>5</span>
8 0
3 years ago
Write the equation ∣4−r/3∣=7 as two separate equations, and enter each equation in its own answer box below. Neither of your equ
Naddik [55]

Answer:

4 - r/3 = 7   and 4 - r/3 = -7

Step-by-step explanation:

absolute value equations get split into a positive equation and a negative equation

4 - r/3 = 7   and 4 - r/3 = -7


6 0
3 years ago
A migrating bird flies 315 miles in 15 hours. How many miles does it fly in 7 ​hours?
cluponka [151]

Answer:

147

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
I will mark brainliest, please help !!
Elena L [17]

Answer:

x = 5/(a-b+3)

Step-by-step explanation:

ax+3x=bx+5

Collect all the terms that has x:

ax-bx+3x = 5 (Subtracting bx both sides)

Take out the x!

x(a-b+3) =5

Divide (a-b+3) both sides to solve for x

x = 5/(a-b+3)

Hope this helps!

Would really appreicate the brainliest!

7 0
3 years ago
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