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Harrizon [31]
3 years ago
15

under the tree ba dum ba dum under the tree ba dum ba dum i am a dog under the log under the tree ba dum ba dum

Mathematics
2 answers:
Sidana [21]3 years ago
7 0

Answer:

.______________.

Step-by-step explanation:

AleksAgata [21]3 years ago
6 0

Answer:

Under the sea bam ba bam  Under the sea bam ba bam  I am a crab and im under the sea

Step-by-step explanation:

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Can get help with this ;)
ivolga24 [154]
The answer is B i think!
4 0
3 years ago
Read 2 more answers
Answer ASAP please
Vikki [24]

<u>Answer</u>:

h = 16  ||    solution after squaring: x = -0.683<em> or </em>x = -7.32

<u>steps by fieranswererft</u>:

Given: x^2+8x+5=0

Take half of the x term and square it

  • [8*\frac{1}{2} ]^2=16

  • x^2+8x+16=- 5+16

  • (x+4)^2=-5+16

  • (x+4)^2=11

  • x+4 = \pm \sqrt{11}

  • x = \pm \sqrt{11}-4

  • x = -0.683<em> or </em>x = -7.32
7 0
3 years ago
Find the volume of a cube with side length of 7 in.
anastassius [24]

Answer: 343 in³

Explanation: In this problem, we're asked to find the volume of a cube.

It's important to understand that a cube is a type of rectangular prism and the formula for the volume of a rectangular prism is shown below.

<em>Volume = length × width × height</em>

In a cube however, the length, width, and height are all the same. So we can use the formula side × side × side instead.

So the formula for the volume of a cube is side × side × side or s³.

So to find the volume of the given cube, since each side has a length of 7 inches, we can plug this information into the formula to get (7 in.)³ or (7 in.)(7 in.)(7 in).

7 x 7 is 49 and 49 x 7 is 343.

So we have 343 in³.

So the volume of the given cube is 343 in³.

8 0
3 years ago
I need help on number 16 these instructions say to solve these equations by cross multiplying
Grace [21]

Answer:

  15.  x = 4

  16.  a = 19

Step-by-step explanation:

"Cross multiply" essentially means "multiply both sides of the equation by the product of the denominators."

__

<h3>15.</h3>

  \dfrac{x}{6}=\dfrac{2}{3}\\\\3(x)=6(2)\qquad\text{"cross multiply"}\\\\\boxed{x=4}\qquad\text{divide by 3}

This is an example of a problem in which cross-multiplying introduces the need for an extra step: divide by 3. Had we simply multiplied by the denominator of the x-term, we would have been finished in one step:

  x = 6(2/3) = 4

That is, rather than multiplying by the <em>product of the denominators</em>, sometimes the problem can be solved more easily if you multiply by their <em>least common multiple</em>.

__

<h3>16.</h3>

  \dfrac{a+1}{a+5}=\dfrac{a-4}{a-1}\\\\(a-1)(a+1)=(a+5)(a-4)\qquad\text{"cross multiply"}\\\\a^2-1=a^2+a-20\qquad\text{simplify}\\\\\boxed{19=a}\qquad\text{add $20-a^2$}

8 0
3 years ago
Please help me with precalculus??<br>linear and angular speed
Anit [1.1K]
13)

there are 2π radians in 1 revolution, and there are 60 seconds in 1 minute, so keeping that in mind, then,

\bf \cfrac{4\underline{\pi} }{5~\underline{s}}\cdot \cfrac{rev}{2\underline{\pi} }\cdot \cfrac{60~\underline{s}}{min}\implies \cfrac{4\cdot 60~rev}{5\cdot 2~min}\implies \cfrac{240~rev}{10~min}\implies 24\frac{rev}{min}

14)

 \bf \textit{linear velocity}\\\\&#10;v=rw\quad &#10;\begin{cases}&#10;r=radius\\&#10;w=angular~speed\\&#10;----------\\&#10;v=32\frac{m}{sec}\\&#10;w=100\frac{rev}{min}&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;\textit{let's convert \underline{w} to }\frac{radians}{sec}

\bf \cfrac{100~\underline{rev}}{\underline{min}}\cdot \cfrac{2\pi }{\underline{rev}}\cdot \cfrac{\underline{min}}{60~sec}\implies \cfrac{100\cdot 2\pi }{60~sec}\implies \cfrac{10\pi }{3~sec}\implies \cfrac{10\pi }{3}\frac{radians}{sec}\\\\&#10;-------------------------------\\\\&#10;v=rw\implies \cfrac{v}{w}=r\implies \cfrac{\frac{30~m}{sec}}{\frac{10\pi }{3~sec}}\implies r=\cfrac{30~m}{\underline{sec}}\cdot \cfrac{3~\underline{sec}}{10\pi }&#10;\\\\\\&#10;r=\cfrac{90}{10\pi }m

15)

what is the radians per seconds "w" in revolutions per minute?  just another conversion like in 13)

\bf \cfrac{\underline{\pi} }{3~\underline{sec}}\cdot \cfrac{rev}{2\underline{\pi }}\cdot \cfrac{60~\underline{sec}}{min}\implies \cfrac{60 ~rev}{3\cdot 2 ~min}\implies \cfrac{60 ~rev}{6 ~min}\implies 10\frac{rev}{min}
4 0
4 years ago
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