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Firlakuza [10]
2 years ago
7

HELP ASAP PLEASE!!

Mathematics
2 answers:
Vlad [161]2 years ago
5 0

Answer:

From the origin, move 0.5 unit to the left along the x-axis and 1 uni

Step-by-step explanation:

Thepotemich [5.8K]2 years ago
4 0

Answer:

From the origin, move 0.5 unit to the left along the x-axis and 1 unit vertically down, and place the point.

Step-by-step explanation:

hope this helps! :}

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The sum of prime number<br> less than x is 58<br> find an integer value for x
s344n2d4d5 [400]

Answer:

17

but it can be 18 too

cuz the q doesn't tell us that the value of x has to be a prime no.

Step-by-step explanation:

2+3+5+7+11+13+17=58

6 0
3 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
3 years ago
What are the solutions to the equation (2x-5)(3x-1)=0?
lutik1710 [3]
(2x-5)(3x-1)=0

2x-5 = 0      or   3x-1= 0
2x = 5               3x = 1
x = 5/2              x = 1/3

Answer: x=5/2; x=1/3


6 0
3 years ago
Read 2 more answers
What is the selling price if the cost is $1,260.45 and the markup is $396.00
iren2701 [21]
The answer is 1656.45
5 0
3 years ago
Read 2 more answers
The length of a rectangle is three times its width. If the area of the rectangle is 243 m squared, find it’s perimeter
vlabodo [156]

Answer: 72

Step-by-step explanation:

L= 3W

area of a rectangle  A= LxW

replace L with 3 W

A=3W*W= 3w^2

243=3W^2

243/3=W^2

81=w^2, and W=9

L=3*9=27

P= (L+W)=2(27+9)=72

3 0
3 years ago
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